12V+ 8K + Io √xuk 2K m Vref=0 R K uk 2 Find I° by using nodal > 12:38 م 12:38 م
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- Can you solve part d and show all the working thank you. Answer: 8.293 + j 7.2Using superposition, determine the current through the inductance XL for each network in the figureDefine what is used to determine the "steady state" of the charge/discharge phase of an RC Circuit. Which of the two phases takes longer to reach steady state for this circuit, explain.
- Two impedances of Z = 100 +j50 Q and Z2 = 20 -j20 Q are connected in series. what is the magnitude of the equivalent impedance in 2? %3D %3D Your Answer: AnswerKindly choose the appropriate and best answer.0 !!! a *Further Engineering Mathematic X + File | C:/Users/user/Downloads/Further%20Engineering%20MathematicsAssignment-2.pdf Draw T Read aloud CD 9. The two complex numbers V and W represent two reactances connected in series. Calculate the total reactance by finding their sum. AF 3+j4 B = 4-j5 C = 5-j2 D=1-j3 E = 2 +j3FF" FF 4+j1 3 of 4 10. The complex numbers V and W represent two force vectors. Place them on an Argand diagram and calculate the difference between them. 11. Use your given values of V and W to represent the reactances Z₁, Z₂ (as shown in the circuit diagram). Calculate the current flowing in the circuit in polar form if the voltage is v = 1220° and V i = ZTotal Z₁ Z₂ o J (¹) ENG T 60 11:16 PM 3/17/2023 x
- Perform the indicated operations, and express the answer in both rectangular and polar forms. 2+j3 1+8/90° Report your answer so that all angles are in the range of 0 degrees to positive 180 degrees. The rectangular form for the given function is The polar form for the given function is 8 2- OHow can i set up a supernode equation for this diagram? Is the nodes between V1 a super node?24. Find V a) 25√22-5° V b) 25√2285° V c) 25√22175° V d) 25√22-95°V e) none of these 50240° V 25 Ω ww ell 5:2 ell. 160 j100V
- Convert the following to polar form and computethe product. Compare the result with that obtainedusing rectangular form.a. (50 + j10) (4 + j8)b. (j2 − 2) (4 + j5) (2 +j7)Need help with part cOhmic components have a V-I curve O Non-linear VI curve. Parabolic VI curve. Sinusoidal VI curve. Straight line VI curve.