12. Calculate the energy released, in kJ, when 1.00 mol U-238 isotopes (nuclear mass = 238.05078 amu) decays via a-particle emission to form thorium-234 (nuclear mass = 234.03596 amu). The nuclear mass of helium-4 is 4.002603 amu. The speed of light 2.997925×108 m/s and 1 amu = 1.660538×10-²4 g Answer: 1.10×10¹2 J or 1.10 x 10⁹ kJ =
12. Calculate the energy released, in kJ, when 1.00 mol U-238 isotopes (nuclear mass = 238.05078 amu) decays via a-particle emission to form thorium-234 (nuclear mass = 234.03596 amu). The nuclear mass of helium-4 is 4.002603 amu. The speed of light 2.997925×108 m/s and 1 amu = 1.660538×10-²4 g Answer: 1.10×10¹2 J or 1.10 x 10⁹ kJ =
Chapter10: Radioactivity And Nuclear Processes
Section: Chapter Questions
Problem 10.51E
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![12. Calculate the energy released, in kJ, when 1.00 mol U-238 isotopes (nuclear mass=
238.05078 amu) decays via a-particle emission to form thorium-234 (nuclear mass =
234.03596 amu). The nuclear mass of helium-4 is 4.002603 amu. The speed of light =
2.997925×108 m/s and 1 amu = 1.660538×10-24 g
Answer: 1.10×10¹2 J or 1.10 x 10⁹ kJ](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F08580f35-fcc8-4d14-8a5f-ec9170ee9e11%2F2faf2b93-81b5-49b3-a809-6ebc8f76a976%2Fjuc3n96_processed.png&w=3840&q=75)
Transcribed Image Text:12. Calculate the energy released, in kJ, when 1.00 mol U-238 isotopes (nuclear mass=
238.05078 amu) decays via a-particle emission to form thorium-234 (nuclear mass =
234.03596 amu). The nuclear mass of helium-4 is 4.002603 amu. The speed of light =
2.997925×108 m/s and 1 amu = 1.660538×10-24 g
Answer: 1.10×10¹2 J or 1.10 x 10⁹ kJ
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