11100001 1000000000010001 01110111 P6. Consider a datagram network using 8-bit host addresses. Suppose a router uses longest prefix matching and has the following forwarding table: Prefix Match Interface 00 010 1. 011 10 2 11 3 For each of the four interfaces, give the associated range of destination host addresses and the number of addresses in the range.
11100001 1000000000010001 01110111 P6. Consider a datagram network using 8-bit host addresses. Suppose a router uses longest prefix matching and has the following forwarding table: Prefix Match Interface 00 010 1. 011 10 2 11 3 For each of the four interfaces, give the associated range of destination host addresses and the number of addresses in the range.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
Can you please explain why these are the answers to this problem. I don’t get how to calculate the number of addresses for the interface please tell me how I do that .
![Problem
Destination Address R
00000000
through
Link Interface
00111111
01000000
through
01011111
1
01100000
through
01111111
10000000
through
10111111
11000000
through
11111111
3
2° = 64
2 = 32
number of addresses for interface 0 =
number of addresses for interface 1=
number of addresses for interface 2 2°+ 2 = 64+ 32 = 96
number of addresses for interface 3 =
2 64](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff6cb2505-b713-4a1c-ba91-20ef50863b3d%2Fcc18f0dd-b47c-45bc-a740-2895d7ef39a1%2F3om5v4q_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problem
Destination Address R
00000000
through
Link Interface
00111111
01000000
through
01011111
1
01100000
through
01111111
10000000
through
10111111
11000000
through
11111111
3
2° = 64
2 = 32
number of addresses for interface 0 =
number of addresses for interface 1=
number of addresses for interface 2 2°+ 2 = 64+ 32 = 96
number of addresses for interface 3 =
2 64
![11100001 U10000001000011 00111100
11100001 10000000 00010001 01110111
P6. Consider a datagram network using 8-bit host addresses. Suppose a router
uses longest prefix matching and has the following forwarding table:
Prefix Match
Itarfoce
00
010
011
2.
10
2.
11
3.
For each of the four interfaces, give the associated range of destination host
addresses and the number of addresses in the range.
THE NETWORK LAYER: DATA PLANE
a](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff6cb2505-b713-4a1c-ba91-20ef50863b3d%2Fcc18f0dd-b47c-45bc-a740-2895d7ef39a1%2Fckgsgfw_processed.jpeg&w=3840&q=75)
Transcribed Image Text:11100001 U10000001000011 00111100
11100001 10000000 00010001 01110111
P6. Consider a datagram network using 8-bit host addresses. Suppose a router
uses longest prefix matching and has the following forwarding table:
Prefix Match
Itarfoce
00
010
011
2.
10
2.
11
3.
For each of the four interfaces, give the associated range of destination host
addresses and the number of addresses in the range.
THE NETWORK LAYER: DATA PLANE
a
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