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11.6. The following pair of compounds produces different products depending on the base and order of mixing. a). Predict the major product formed when the two compounds are mixed with K2CO3. NH2 Br K,CO, + HO b). Predict the major product formed when the amino alcohol is treated with NaH followed by benzvlbromide. NH2 1) NaH 2) Br HO c). Provide an explanation for why the reactions in parts (a) and (b) above give different products.

11.6. The following pair of compounds produces different products depending on the base and order of mixing. a). Predict the major product formed when the two compounds are mixed with K2CO3. NH2 Br K,CO, + HO b). Predict the major product formed when the amino alcohol is treated with NaH followed by benzvlbromide. NH2 1) NaH 2) Br HO c). Provide an explanation for why the reactions in parts (a) and (b) above give different products.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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11.6. The following pair of compounds produces different products depending on the base and order of mixing. a). Predict the major product formed when the two compounds are mixed with K2CO3. NH2 `Br K,CO3 HO b). Predict the major product formed when the amino alcohol is treated with NaH followed by benzvlbromide. NH2 1) NaH 2) `Br HO c). Provide an explanation for why the reactions in parts (a) and (b) above give different products.
Transcribed Image Text:11.6. The following pair of compounds produces different products depending on the base and order of mixing. a). Predict the major product formed when the two compounds are mixed with K2CO3. NH2 `Br K,CO3 HO b). Predict the major product formed when the amino alcohol is treated with NaH followed by benzvlbromide. NH2 1) NaH 2) `Br HO c). Provide an explanation for why the reactions in parts (a) and (b) above give different products.
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