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11.40 predict products A-D ame diynedg S-ivdlem 1. NaH PBr3 A В C 2. 3. Н

11.40 predict products A-D ame diynedg S-ivdlem 1. NaH PBr3 A В C 2. 3. Н

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The image depicts a multi-step organic chemistry reaction sequence involving the transformation of a benzene derivative. The text and figures appear as follows: 1. **Starting Structure**: A benzene ring with a propene group (allyl group) attached. 2. **Step A**: Reaction with H₂O and a proton (H⁺) to form an intermediate epoxide. This involves the addition of an oxygen atom across the alkene, forming a three-membered ring with an oxygen atom. The positive charge indicates the reaction environment or condition is acidic. 3. **Step B**: Transformation of the epoxide intermediate with NH₃ to produce a new structure with an amine group. The ammonia opens the epoxide ring, leading to the formation of molecule B. 4. **Step C**: Further reaction with Pb₃O₄, which likely acts as an oxidation agent. This step modifies molecule B to produce molecule C, which contains distinct changes in functional groups or oxidation states. 5. **Step D**: The final reaction involves NaOH, suggesting a basic reaction condition, transforming molecule C into the final product, molecule D. The sequence, labeled "11.40 Predict products A-D," emphasizes predicting the outcome at each step of the series. This exercise typically helps students understand the reactivity and mechanisms involved in organic synthesis pathways. No graphs or diagrams are explained in further detail as the focus is on the chemical transformations.
Transcribed Image Text:The image depicts a multi-step organic chemistry reaction sequence involving the transformation of a benzene derivative. The text and figures appear as follows: 1. **Starting Structure**: A benzene ring with a propene group (allyl group) attached. 2. **Step A**: Reaction with H₂O and a proton (H⁺) to form an intermediate epoxide. This involves the addition of an oxygen atom across the alkene, forming a three-membered ring with an oxygen atom. The positive charge indicates the reaction environment or condition is acidic. 3. **Step B**: Transformation of the epoxide intermediate with NH₃ to produce a new structure with an amine group. The ammonia opens the epoxide ring, leading to the formation of molecule B. 4. **Step C**: Further reaction with Pb₃O₄, which likely acts as an oxidation agent. This step modifies molecule B to produce molecule C, which contains distinct changes in functional groups or oxidation states. 5. **Step D**: The final reaction involves NaOH, suggesting a basic reaction condition, transforming molecule C into the final product, molecule D. The sequence, labeled "11.40 Predict products A-D," emphasizes predicting the outcome at each step of the series. This exercise typically helps students understand the reactivity and mechanisms involved in organic synthesis pathways. No graphs or diagrams are explained in further detail as the focus is on the chemical transformations.
Expert Solution
Step 1
  • The first step of the reaction is the hydration of alkene in presence of an acid catalyst. The alkene reacts with water to forms alcohol.
  • The second step of the reaction is an epoxide ring-opening reaction in presence of a base. This reaction form product "B".
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