1. Consider the conversion of dichloroethane (C2H4Cl2) to Cl2 and ethylene (C2H4) gases: C2H4Cl2 (g) Cl2(g) + C2H4 (g) At 298K and standard conditions this reaction is non-spontaneous. A.) Without doing any calculations, and just by looking at the reaction, deduce the sign of DSo. The sign of DSo is . I know this because (give two reasons): B.) Calculate DSo from the given values of So for the reactants and products. So(C2H4Cl2,g) = 306.5 J/Kmol ; So (Cl2,g)= 223.07 J/Kmol; So (C2H4,g) = 219.36 J/Kmol DSo = (give units) C.) Using only the information you know so far, what must the sign of DHo be? Explain how you know this. Now calculate the value of DHo using the values of DHfo given here: DHfo(C2H4Cl2,g) = -132.2 J/Kmol ; DHfo (C2H4,g) = 52.4 J/Kmol DHo = (give units) What is the value of Kp at 298 K?
1. Consider the conversion of dichloroethane (C2H4Cl2) to Cl2 and ethylene (C2H4) gases:
C2H4Cl2 (g) Cl2(g) + C2H4 (g)
At 298K and standard conditions this reaction is non-spontaneous.
A.) Without doing any calculations, and just by looking at the reaction, deduce the sign of DSo.
The sign of DSo is . I know this because (give two reasons):
B.) Calculate DSo from the given values of So for the reactants and products.
So(C2H4Cl2,g) = 306.5 J/Kmol ; So (Cl2,g)= 223.07 J/Kmol; So (C2H4,g) = 219.36 J/Kmol
DSo = (give units)
C.) Using only the information you know so far, what must the sign of DHo be?
Explain how you know this.
Now calculate the value of DHo using the values of DHfo given here:
DHfo(C2H4Cl2,g) = -132.2 J/Kmol ; DHfo (C2H4,g) = 52.4 J/Kmol
DHo = (give units)
What is the value of Kp at 298 K?
Trending now
This is a popular solution!
Step by step
Solved in 3 steps
