11.1 The centre of mass m₁ is located at distance r from the centre of mass m₂, and m₁ undergoes a circular motion at speed, v, due to m₂. Upon doubling the magnitude of m, and halving the separation distance between the centres of the two masses, what shall the speed of m₁ become in terms of v?

College Physics
11th Edition
ISBN:9781305952300
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Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question 11
11.1 The centre of mass m₁ is located at distance r
from the centre of mass m₂, and m₁ undergoes a circular
motion at speed, v, due to m₂. Upon doubling the
magnitude of m₁ and halving the separation distance
between the centres of the two masses, what shall the
speed of m₁ become in terms of v?
(Show the workings; i.e. show how you get the answer.)
11.2 A 120 g mass, attached to 20 cm long string,
undergoes vertical circular motion at 1.7 m.s¹¹. Determine
the tension on a string at an instant when the stone is
150 mm above the lowest point of its motion. (Ignore the
diameter of the stone)
Transcribed Image Text:Question 11 11.1 The centre of mass m₁ is located at distance r from the centre of mass m₂, and m₁ undergoes a circular motion at speed, v, due to m₂. Upon doubling the magnitude of m₁ and halving the separation distance between the centres of the two masses, what shall the speed of m₁ become in terms of v? (Show the workings; i.e. show how you get the answer.) 11.2 A 120 g mass, attached to 20 cm long string, undergoes vertical circular motion at 1.7 m.s¹¹. Determine the tension on a string at an instant when the stone is 150 mm above the lowest point of its motion. (Ignore the diameter of the stone)
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