11.1 The centre of mass m₁ is located at distance r from the centre of mass m₂, and m₁ undergoes a circular motion at speed, v, due to m₂. Upon doubling the magnitude of m₁ and halving the separation distance between the centres of the two masses, what shall the speed of m₁ become in terms of v?
11.1 The centre of mass m₁ is located at distance r from the centre of mass m₂, and m₁ undergoes a circular motion at speed, v, due to m₂. Upon doubling the magnitude of m₁ and halving the separation distance between the centres of the two masses, what shall the speed of m₁ become in terms of v?
Related questions
Question
This is urgent please. I need t like now. I will appreciate
Transcribed Image Text:Question 11
11.1 The centre of mass m₁ is located at distance r
from the centre of mass m₂, and m₁ undergoes a circular
motion at speed, v, due to m₂. Upon doubling the
magnitude of m₁ and halving the separation distance
between the centres of the two masses, what shall the
speed of m₁ become in terms of v?
(Show the workings; i.e. show how you get the answer.)
11.2 A 120 g mass, attached to 20 cm long string,
undergoes vertical circular motion at 1.7 m.s¹¹. Determine
the tension on a string at an instant when the stone is
150 mm above the lowest point of its motion. (Ignore the
diameter of the stone)
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps
