1. In the figure particles 1 and 2 of charge qı = q2 = +5.00 × 10-19 C are on a y axis at distance d = 18.00 cm from the origin. Particle 3 of charge q3 = +3.20 × 10-19 C is moved along the x axis at x = 28.00 cm. At what values of electric potential will on the third particle from the other two particles be?
1. In the figure particles 1 and 2 of charge qı = q2 = +5.00 × 10-19 C are on a y axis at distance d = 18.00 cm from the origin. Particle 3 of charge q3 = +3.20 × 10-19 C is moved along the x axis at x = 28.00 cm. At what values of electric potential will on the third particle from the other two particles be?
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![### Electric Potential on a Particle
#### Problem Statement:
1. In the figure below, particles 1 and 2 each have a charge \( q_1 = q_2 = +5.00 \times 10^{-19} \) C and are located on the y-axis at distances \( d = 18.00 \) cm from the origin. Particle 3 with a charge \( q_3 = +3.20 \times 10^{-19} \) C is moved along the x-axis at \( x = 28.00 \) cm. What is the electric potential of the third particle from the other two particles?
---
#### Diagram Description:
- The diagram is a Cartesian coordinate plot with x and y axes.
- Particle 1 is located at (0, 18) cm.
- Particle 2 is located at (0, -18) cm.
- Particle 3 is located at (28, 0) cm on the x-axis.
- The distances between the particles and the origin are marked as \( d \).
#### Visual Representation:
1. \[
\begin{array}{c}
y \\
\leftarrow \\
1 \quad \text{(0,18 cm)} \\
↑ \quad ↑ \quad d \\
↓ \quad ↓ d \\
2 \quad \text{(0, -18 cm)} \\
\downarrow
\end{array}
\]
\[
\begin{array}{c}
\text{Particle 3 at (28 cm, 0 cm)}
\end{array}
\]
#### Solution Steps:
1. Calculate the distance between each of the paired particles.
2. Use the formula for electric potential to determine the potential on particle 3 due to particles 1 and 2.
#### Electric Potential Formula:
The electric potential \( V \) due to a charge \( q \) at a distance \( r \) is given by:
\[ V = \frac{k \cdot q}{r} \]
where \( k \) is the Coulomb constant (\( 8.99 \times 10^9 \) N m²/C²).
Use the Pythagorean theorem to find the distance \( r \) from particles 1 and 2 to particle 3:
\[ r = \sqrt{x^2 + y^2} \]
### Detailed Explanation:
For continued and thorough analysis, students are encouraged to](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F225ba3ae-b794-4861-a1fb-e750fe881882%2F68fb731a-5f73-4fe3-b9df-a7b7f945a13f%2Fwlx5gll_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Electric Potential on a Particle
#### Problem Statement:
1. In the figure below, particles 1 and 2 each have a charge \( q_1 = q_2 = +5.00 \times 10^{-19} \) C and are located on the y-axis at distances \( d = 18.00 \) cm from the origin. Particle 3 with a charge \( q_3 = +3.20 \times 10^{-19} \) C is moved along the x-axis at \( x = 28.00 \) cm. What is the electric potential of the third particle from the other two particles?
---
#### Diagram Description:
- The diagram is a Cartesian coordinate plot with x and y axes.
- Particle 1 is located at (0, 18) cm.
- Particle 2 is located at (0, -18) cm.
- Particle 3 is located at (28, 0) cm on the x-axis.
- The distances between the particles and the origin are marked as \( d \).
#### Visual Representation:
1. \[
\begin{array}{c}
y \\
\leftarrow \\
1 \quad \text{(0,18 cm)} \\
↑ \quad ↑ \quad d \\
↓ \quad ↓ d \\
2 \quad \text{(0, -18 cm)} \\
\downarrow
\end{array}
\]
\[
\begin{array}{c}
\text{Particle 3 at (28 cm, 0 cm)}
\end{array}
\]
#### Solution Steps:
1. Calculate the distance between each of the paired particles.
2. Use the formula for electric potential to determine the potential on particle 3 due to particles 1 and 2.
#### Electric Potential Formula:
The electric potential \( V \) due to a charge \( q \) at a distance \( r \) is given by:
\[ V = \frac{k \cdot q}{r} \]
where \( k \) is the Coulomb constant (\( 8.99 \times 10^9 \) N m²/C²).
Use the Pythagorean theorem to find the distance \( r \) from particles 1 and 2 to particle 3:
\[ r = \sqrt{x^2 + y^2} \]
### Detailed Explanation:
For continued and thorough analysis, students are encouraged to
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