11. Evaluate the indefinite integral as a power series. In(1 +* dv In(1+x²) dp. х x2n - 1 2n – 1 a. C+ Σ(-1)γ 1, n = 1 n(2n – 1) .2n b. C+ Σ (-1γ- , n = 1 2n? 2n + 1 c. C+ Σ(-1)7 1 n(2n + 1) п%3D1 2n+1 d. C + E(-1)"n(2n+1) n=0 п(2n + 1) 2n e. C+ E(-1)" n(2n + 1) n=0

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