6. Evaluate the following indefinite integral as an infinite series. sin x (a) (-1)". 2n+1 (b) (-1)"+1. 2n+4 (2n + 3)! z2n+1 n=0 (2n + 4)(2n + 3)! n=0 (c) (-1)"+1 (d) E(-1)", z2n+1 (2n + 1)(2n + 3)! 12n+1 n=0 (2n + 1)(2n + 1)! n=0 (e) (-1)". (2n + 1)! n=0
6. Evaluate the following indefinite integral as an infinite series. sin x (a) (-1)". 2n+1 (b) (-1)"+1. 2n+4 (2n + 3)! z2n+1 n=0 (2n + 4)(2n + 3)! n=0 (c) (-1)"+1 (d) E(-1)", z2n+1 (2n + 1)(2n + 3)! 12n+1 n=0 (2n + 1)(2n + 1)! n=0 (e) (-1)". (2n + 1)! n=0
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![6. Evaluate the following indefinite integral as an infinite series.
sin x
x²n+1
x2n+4
C(-1)".
(2n + 3)! (b) L(-1)n+1
22n+1
(a)
n=0
(2n + 4)(2n + 3)!
n=0
(c) (-1)*+1.
(d) E(-1)".
2n+1
(2n + 1)(2n + 3)!
(2n + 1)(2n + 1)!
n=0
(e) (-1)"-
(2n + 1)!
n=0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F97c8dca1-0e99-4cbb-aed2-4da6d5330940%2Fa99eb9aa-10a0-4d7c-9b96-681f69e083eb%2F1lbhi6_processed.png&w=3840&q=75)
Transcribed Image Text:6. Evaluate the following indefinite integral as an infinite series.
sin x
x²n+1
x2n+4
C(-1)".
(2n + 3)! (b) L(-1)n+1
22n+1
(a)
n=0
(2n + 4)(2n + 3)!
n=0
(c) (-1)*+1.
(d) E(-1)".
2n+1
(2n + 1)(2n + 3)!
(2n + 1)(2n + 1)!
n=0
(e) (-1)"-
(2n + 1)!
n=0
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