11. A suspension of milk of magnesia, Mg(OH)2, is analysed by back titration. A 1.0391 g sample is dissolved by the addition of 25.0 mL of 0.1112 M perchloric acid, HCIO4. The excess perchloric acid is titrated with 10.55 mL of 0.1417 M sodium hydroxide, NaOH solution to reach end point. Mg(OH)2 + 2HC104 HCIO4 +NaOH Mg(CI)4)2 + 2H₂O NaClO4+H₂O a) Calculate the weight percentage of magnesium hydroxide in the sample. b) Sketch a labelled titration curve of a strong acid, 50.0 mL 0.100 M reacting with a strong base of similar concentration.
11. A suspension of milk of magnesia, Mg(OH)2, is analysed by back titration. A 1.0391 g sample is dissolved by the addition of 25.0 mL of 0.1112 M perchloric acid, HCIO4. The excess perchloric acid is titrated with 10.55 mL of 0.1417 M sodium hydroxide, NaOH solution to reach end point. Mg(OH)2 + 2HC104 HCIO4 +NaOH Mg(CI)4)2 + 2H₂O NaClO4+H₂O a) Calculate the weight percentage of magnesium hydroxide in the sample. b) Sketch a labelled titration curve of a strong acid, 50.0 mL 0.100 M reacting with a strong base of similar concentration.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:11. A suspension of milk of magnesia, Mg(OH)2, is analysed by back titration. A 1.0391 g sample
is dissolved by the addition of 25.0 mL of 0.1112 M perchloric acid, HCIO4. The excess perchloric
acid is titrated with 10.55 mL of 0.1417 M sodium hydroxide, NaOH solution to reach end point.
Mg(OH)2 + 2HC104
HCIO4 +NaOH
Mg(CI)4)2 + 2H₂O
NaClO4+H₂O
a) Calculate the weight percentage of magnesium hydroxide in the sample.
b) Sketch a labelled titration curve of a strong acid, 50.0 mL 0.100 M reacting with a
strong base of similar concentration.
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