11) Which is the reduction half reaction for a Mg and Ag electrochemical cell? (The reaction is spontaneous.) a) Mg* + 2e → Mg(s) (Mg gains electrons) b) Mg(s) → Mg + 2e (Mg loses electrons) c) Ag + e> Ag (s) (Ag gains electrons) d) Ag(s) → Ag* + e- (Ag loses electrons) 12) In an electrochemical cell made of Al and Cu, Al loses 3 electrons per atom while Cu gains 2 electrons per atom. What are the two half-reactions (oxidation and reduction) combined together and balanced? (A total of 6 electrons should be lost and gained.) a) Al* + Cu(s) → Al (s) + Cu²* b) 2Al* + 3Cu(s) → 2AI (s) + 3Cu2* c) Al (s) + Cu²+ → Al* + Cu(s) d) 2Al (s) + 3CU2*→ 2AI³* + 3Cu(s)

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Chapter1: Chemical Foundations
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**Electrochemical Cell Reactions**

**Question 11:** Which is the reduction half reaction for a Mg and Ag electrochemical cell? (The reaction is spontaneous.)

a) \( \text{Mg}^{2+} + 2e^- \rightarrow \text{Mg(s)} \) (Mg gains electrons)

b) \( \text{Mg(s)} \rightarrow \text{Mg}^{2+} + 2e^- \) (Mg loses electrons)

c) \( \text{Ag}^+ + e^- \rightarrow \text{Ag(s)} \) (Ag gains electrons)

d) \( \text{Ag(s)} \rightarrow \text{Ag}^+ + e^- \) (Ag loses electrons)

**Question 12:** In an electrochemical cell made of Al and Cu, Al loses 3 electrons per atom while Cu gains 2 electrons per atom. What are the two half-reactions (oxidation and reduction) combined together and balanced? (A total of 6 electrons should be lost and gained.)

a) \( \text{Al}^{3+} + \text{Cu(s)} \rightarrow \text{Al(s)} + \text{Cu}^{2+} \)

b) \( 2\text{Al}^{3+} + 3\text{Cu(s)} \rightarrow 2\text{Al(s)} + 3\text{Cu}^{2+} \)

c) \( \text{Al(s)} + \text{Cu}^{2+} \rightarrow \text{Al}^{3+} + \text{Cu(s)} \)

d) \( 2\text{Al(s)} + 3\text{Cu}^{2+} \rightarrow 2\text{Al}^{3+} + 3\text{Cu(s)} \) 

(Note: There are no graphs or diagrams to explain.)
Transcribed Image Text:**Electrochemical Cell Reactions** **Question 11:** Which is the reduction half reaction for a Mg and Ag electrochemical cell? (The reaction is spontaneous.) a) \( \text{Mg}^{2+} + 2e^- \rightarrow \text{Mg(s)} \) (Mg gains electrons) b) \( \text{Mg(s)} \rightarrow \text{Mg}^{2+} + 2e^- \) (Mg loses electrons) c) \( \text{Ag}^+ + e^- \rightarrow \text{Ag(s)} \) (Ag gains electrons) d) \( \text{Ag(s)} \rightarrow \text{Ag}^+ + e^- \) (Ag loses electrons) **Question 12:** In an electrochemical cell made of Al and Cu, Al loses 3 electrons per atom while Cu gains 2 electrons per atom. What are the two half-reactions (oxidation and reduction) combined together and balanced? (A total of 6 electrons should be lost and gained.) a) \( \text{Al}^{3+} + \text{Cu(s)} \rightarrow \text{Al(s)} + \text{Cu}^{2+} \) b) \( 2\text{Al}^{3+} + 3\text{Cu(s)} \rightarrow 2\text{Al(s)} + 3\text{Cu}^{2+} \) c) \( \text{Al(s)} + \text{Cu}^{2+} \rightarrow \text{Al}^{3+} + \text{Cu(s)} \) d) \( 2\text{Al(s)} + 3\text{Cu}^{2+} \rightarrow 2\text{Al}^{3+} + 3\text{Cu(s)} \) (Note: There are no graphs or diagrams to explain.)
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