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ng question Fe3*(aq) + 3e → Fe(s) E° = -0.04V Ni+2 (ag) + 2e > Ni(s) E° = -0.24V Zn2*(aq) + 2e → Zn(s) E° = -0.76V Which half-cells can be connected to provide the galvanic cell with the greatest voltage? a. Fe3+ (aq) + 3e → Fe (s) and Ni2+ (aq) + 2e" → Ni (s) b. Fe3+ (ag) + 3e > Fe (s) and Zn2+ (aq) + 2e → Zn (s) Ni2+ (ag) + 2e → Ni (s) and Zn2* (aq) + 2e → Zn (s) C. O Band C A B

ng question Fe3*(aq) + 3e → Fe(s) E° = -0.04V Ni+2 (ag) + 2e > Ni(s) E° = -0.24V Zn2*(aq) + 2e → Zn(s) E° = -0.76V Which half-cells can be connected to provide the galvanic cell with the greatest voltage? a. Fe3+ (aq) + 3e → Fe (s) and Ni2+ (aq) + 2e" → Ni (s) b. Fe3+ (ag) + 3e > Fe (s) and Zn2+ (aq) + 2e → Zn (s) Ni2+ (ag) + 2e → Ni (s) and Zn2* (aq) + 2e → Zn (s) C. O Band C A B

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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For the following question, consider standard versions of the half-cells shown below: Fe*(aq) + 3e → Fe(s) E° = -0.04V Ni+2 (aq) + 2e > Ni(s) E° = -0.24V Zn2+(aq) + 2e → Zn(s) E° = -0.76V Which half-cells can be connected to provide the galvanic cell with the greatest voltage? a. Fe3+ (aq) + 3e Fe (s) Ni2+ (aq) + 2e → Ni (s) and b. Fe3+ (aq) + 3e > Fe (s) Zn2+ and (aq) + 2e → Zn (s) Ni2+ (aq) + 2e → Ni (s) Zn2* (aq) + 2e → Zn (s) C. and B and C O A O B
Transcribed Image Text:For the following question, consider standard versions of the half-cells shown below: Fe*(aq) + 3e → Fe(s) E° = -0.04V Ni+2 (aq) + 2e > Ni(s) E° = -0.24V Zn2+(aq) + 2e → Zn(s) E° = -0.76V Which half-cells can be connected to provide the galvanic cell with the greatest voltage? a. Fe3+ (aq) + 3e Fe (s) Ni2+ (aq) + 2e → Ni (s) and b. Fe3+ (aq) + 3e > Fe (s) Zn2+ and (aq) + 2e → Zn (s) Ni2+ (aq) + 2e → Ni (s) Zn2* (aq) + 2e → Zn (s) C. and B and C O A O B
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