Write a baiancedequation for theoverall reactionthat powers thecell. Be sure thereaction isspontaneous aswritten.Do you haveenoughinformation tocalculate the cell.voltage understandardconditions?YesNoIf you said it waspossible tocalculate the cllvoltage, do so andenter your answer Vhere. Be sure youranswer has thecorrect number ofsionificant diaits. A chemist designs a galvanic cell that uses these two half-reactions:half-reactionstandard reduction potentialN,(g)+4H,O(1)+4e - N,H,(aq)+4 OH (aq)E =-1.16 VredZn (aq)+2e2+Zn(s)E =-0.763 VredAnswer the following questions about this cell.Write a balancedequation for thehalf-reaction thathappens at thecathode.Write a balancedequation for thehalf-reaction thethappens at theanode.Write a balanced

In these cells chemical energy is converted into electrical energy The one whcih is having high…

Answered: half-reaction standard reduction…

half-reaction standard reduction potentia N,(9)+4H,O(1)+4e N,H,(aq)+4OH (aq) E=-1.16 V red Zn(aq)+2e ,2+, Zn(s) E=-0.763 V 'red Answer the following questions about this cell.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Consider the following standard reduction potentials. O₂(g) + 2H₂O(1) +4 Ca²+ (aq) +2e - 40H (aq) E° = 0.401 V Ca(s) E= -2.868 V E°
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What statement about a galvanic cell constructed with Cu*/Cu and Fe2*/Fe is correct? Standard reduction E°red, V potentials Cu* + e ---> Cu +0.52 Fe2+ + 2e ---> Fe |-0.44 O Fe2*(aq) is reduced at the cathode. O Fe(s) will reduce Cu*(aq). Fe(s) is a stronger oxidizing agent than Cu(s). O The standard cell potential (E°cell) is +1.40 V.
If you said it was possible to calculate the cell voltage, do so and enter your answer here. Round your Ov answer to 2 significant digits.
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half-reaction standard reduction potential Br,(1)+2e - 2 Br (aq) =+1.065 V red MnO, (aq)+2 H,0(1)+3e MnO,(5)+4 OH (aq) E° =+0.59 V (red Answer the following questions about this cell. Write a balanced equation for the half-reaction that happens at the cathode. Write a balanced equation for the half-reaction that happens at the anode. Write a balanced equation for the overall reaction that powers the cell. Be sure the reaction is spontaneous as written. Do you have enough information to Yes calculate the cell voltage under standard No conditions? If said it was you possible to calculate the cell voltage, do so and enter your answer here. Round your Ov answer to 2 significant digits.
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Consider the following two half-reactions and their standard reduction potentials. N2(g) +H,0(1) E° = 1.766 V MnO, (s) + 2H,0(1) E° = 1.673 V N,0(g) + 2H*(aq) + 2e¯ → MnO,(aq) + 4H*(aq)+3e¯ 1st attempt l See Calculate E°for the spontaneous redox reaction that occurs when these two half-reactions are coupled. V