gA parallel plate,air capacitor of plate.separation 2 'mm and capacitance 1. MF ischarged to 200 V A dielectric of relativePermittivity 50 is now inserted so as to fill thespace: between the plates. () Find the newvalue of capacitance (ii) Find the polarisationcharge on one of the boundaries of thedielectric, (iii) Find the magnitude of thepolarisation of the electric (iv) What is themagnitude of the electric field inside thedielectric?

Given-C0=10-6 Fd=2×10-3 mk=50V=200 Vε0=8.85×10-12F/m

11 A parallel plate air capacitor of plate separation 2 'mm and capacitance 1 pF is charged to $200 V. A dielectric of relative permittivity 50 is now inserted so as to fill the space: between the plates. 6) Find the new value of capacitance (ii) Find the polarisation charge on one of the boundaries of the dielectric, (iii) Find the magnitude of the polarisation of the electric (iv) What is the magnitude of the electric field inside the dielectric?

11 A parallel plate air capacitor of plate separation 2 'mm and capacitance 1 pF is charged to $200 V. A dielectric of relative permittivity 50 is now inserted so as to fill the space: between the plates. 6) Find the new value of capacitance (ii) Find the polarisation charge on one of the boundaries of the dielectric, (iii) Find the magnitude of the polarisation of the electric (iv) What is the magnitude of the electric field inside the dielectric?