11 A parallel plate air capacitor of plate separation 2 'mm and capacitance 1 pF is charged to $200 V. A dielectric of relative permittivity 50 is now inserted so as to fill the space: between the plates. 6) Find the new value of capacitance (ii) Find the polarisation charge on one of the boundaries of the dielectric, (iii) Find the magnitude of the polarisation of the electric (iv) What is the magnitude of the electric field inside the dielectric?
11 A parallel plate air capacitor of plate separation 2 'mm and capacitance 1 pF is charged to $200 V. A dielectric of relative permittivity 50 is now inserted so as to fill the space: between the plates. 6) Find the new value of capacitance (ii) Find the polarisation charge on one of the boundaries of the dielectric, (iii) Find the magnitude of the polarisation of the electric (iv) What is the magnitude of the electric field inside the dielectric?
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A parallel plate,air capacitor of plate.
separation 2 'mm and capacitance 1. MF is
charged to 200 V A dielectric of relative
Permittivity 50 is now inserted so as to fill the
space: between the plates. () Find the new
value of capacitance (ii) Find the polarisation
charge on one of the boundaries of the
dielectric, (iii) Find the magnitude of the
polarisation of the electric (iv) What is the
magnitude of the electric field inside the
dielectric?
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