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You make an air-filled parallel-plate Capacitor having a Capacitance of 272 pF [Co]. You connect your Capacitor to a 240.-V Battery [AV] 0 to charge the plates. Once charged, you disconnect the Battery, and then, place the Capacitor into a pail of water (K = 80).

You make an air-filled parallel-plate Capacitor having a Capacitance of 272 pF [Co]. You connect your Capacitor to a 240.-V Battery [AV] 0 to charge the plates. Once charged, you disconnect the Battery, and then, place the Capacitor into a pail of water (K = 80).

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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You make an air-filled parallel-plate Capacitor having a Capacitance of 272 pF [Co]. You connect your Capacitor to a 240.-V Battery [AV] to charge the plates. Once charged, you disconnect the Battery, and then, place the Capacitor into a pail of water (K = 80). Calculate the new Capacitance in nano-Faradays [C, {nF}]. Remember, nano is: n = X 10-9 Calculate the new Voltage Drop [AVK (V)] across the Capacitor's terminals.
Transcribed Image Text:You make an air-filled parallel-plate Capacitor having a Capacitance of 272 pF [Co]. You connect your Capacitor to a 240.-V Battery [AV] to charge the plates. Once charged, you disconnect the Battery, and then, place the Capacitor into a pail of water (K = 80). Calculate the new Capacitance in nano-Faradays [C, {nF}]. Remember, nano is: n = X 10-9 Calculate the new Voltage Drop [AVK (V)] across the Capacitor's terminals.
Expert Solution
Step 1: Given and Required

The capacitance of air-filled capacitor,

                             C space equals space 272 space p F

Voltage connected across the capacitor,

                             increment V subscript o space equals space 240 space V

The dielectric constant of water,

                              k space equals space 80    

 We need to find,

a) The new capacitance in nano farad.

b) The new voltage drop across the capacitor terminal.

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