Answered: 2. Consider an adjustable… | bartleby

Related questions

Question

100%

2. Consider an adjustable parallel-plate capacitor that is charged and then disconnected from the
battery that charged it. While remaining disconnected what happens to the electric field between
the capacitor's plates (a) if the surface area of the plates is decreased, and (b) if the separation
distance between the plates is decreased? Explain why in both cases.

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 4 images

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

30. A ball hangs from a thread between two vertical capacitor plates. Initially the ball is neutral. Before the capacitor is charged, the ball hangs exactly in the center. a. After the capacitor is charged, is the ball's equilibrium position to the right, to the left, or in the center? Explain.
Please walkthrough A parallel-plate capacitor is connected to a battery and has charge +Q0 and −Q0 on its plates. While the capacitor remains connected to the battery, the separation between the plates is doubled. Explain what will happen to the charge on the capacitor plates and why.
2. A capacitor is made from two square conducting plates, each 10 cm x 10 cm, at a separation of 2.0mm. (a) If air is present between the plates, calculate the capacitance. voltage (b) A potential difference-of 80 V is applied to the two plates. How much charge is on each plate? Make a sketch illustrating the charged capacitor. (c) Calculate the electric field in between the capacitor plates. Make a sketch showing field lines. wont ase about dieletricg (d) A dielectric with &,=40 is inserted between the capacitor plates, but to do so, the plate separation must be increased to 2.5 mm. How does the electric field change in this case if the potential difference is kept constant.
Imagine a parallel plate capacitor with mica between the plates. Suppose the potential difference between the plates is 82V, and there is an electric field between the plates with a strength of 320 N/C. If each plate has an area of 0.030 square meters, a) What is the separation between the plates? b) Find the capacitance of the capacitor. c) How much charge is on each plate? d) How much energy is stored in the capacitor? For each part, explain your reasoning.
2. A charge q = - 2.0 C moves in the opposite direction of a uniform electric field of 100 V/m by a distance of 3.0m. a. The charge is at a point of (a. higher, b. lower, c. same) potential before moving. b. After moving, the potential energy of the charge a. increases. b. decreases. c. does not change. c. What is the change in the potential energy?
25. You have two flat metal plates each of area 1.00 m², with which to construct a parallel- plate capacitor. A) If the capacitor of the device is to be 1.00 F, what must be the separation of the plates? B) Could the capacitor actually be constructed?
2) A. A small spherical object is released from rest in the center (black dot) of the below capacitor. For a positive, negative, and neutral object, explain the direction of any motion of the particle after it's released and whether the motion will be at a constant speed or will accelerate. Ignore gravity. B. Ignoring gravity, say a positively charged spherical object enters the bottom of the same capacitor as in (a) with a velocity pointed directly upwards. Draw a picture that shows the trajectory of the object inside the capacitor using solid lines. Draw a second trajectory with dashed lines to show the object's trajectory if its initial velocity was slower. Repeat these steps for a negatively charged object using a different colored pen/marker. C. An electron is launched from the bottom of the positive plate at a 45° angle to the plate. It does not have sufficient speed to make it to the negative plate. Draw a potential trajectory for the electron. Ignore gravity. +++++ +++++++
3. The gap of a 2 cm by 3 cm parallel plate capacitor is 3 cm. The capacitor is connected to a 12 V battery. A proton is released from rest from the positive side of the capacitor. Determine the (a)capacitance of the capacitor (b) the acceleration of the proton, (b) the time at which the proton strikes the negative plate. Perrino, Anthony hursday regarding CashPlus & the investment . Fe O4 PayPal can view the changes on our website View Onli.. Fe meeting 4. Consider the circuit given below. V= 20 V, RI = 22, R2 = 5 0, R3 = 10 2 and R4 = 8 0. Calculate the current and the voltages across each resistor. meeting O Boot Barn AEL ROBINSON, Your order is on its way! Sign. Fe Ri
3- Two parallel plates of area 100 cm? are given charges of equal magnitudes 8.9 x 107 C but opposite signs. The electric field within the dielectric material filling the space between the plates is 1.4 x 10 V/m. (a) Calculate the dielectric constant of the material. (b) Determine the magnitude of the charge induced on each dielectric surface