11-4.22. The coefficient of friction between the road and the tires the car shown in Fig. P-11-4.22 is 0.60. The car weighs 4000 lb. It rounding a horizontal curve of 600-ft radius at the maximum speed at whic side slipping impends. What is the value of the friction force acting und each wheel? How high above the road must the center of gravity be

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Chapter1: Units, Trigonometry. And Vectors
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The answer is already given. I just need the solution. Also, please make the solution neat and readable. Thank you. Answer: Inner wheels, F= 804 lb Outer wheels, F= 3440 lb, h= 4.02 ft.
 
 
11-4.22. The coefficient of friction between the road and the tires of
the car shown in Fig. P-11-4.22 is 0.60. The car weighs 4000 lb. It is
rounding a horizontal curve of 600-ft radius at the maximum speed at which
side slipping impends. What is the value of the friction force acting under
each wheel? How high above the road must the center of gravity be to
Transcribed Image Text:11-4.22. The coefficient of friction between the road and the tires of the car shown in Fig. P-11-4.22 is 0.60. The car weighs 4000 lb. It is rounding a horizontal curve of 600-ft radius at the maximum speed at which side slipping impends. What is the value of the friction force acting under each wheel? How high above the road must the center of gravity be to
30"
-2'-s"--2'-5"
30°
Figure P-11-4.22
limit this maximum speed by the tendency to overturn?
At inner wheels, F
804 lb;
3440 lb; h =
at outer wheels, F
4.02 ft
Ans.
Transcribed Image Text:30" -2'-s"--2'-5" 30° Figure P-11-4.22 limit this maximum speed by the tendency to overturn? At inner wheels, F 804 lb; 3440 lb; h = at outer wheels, F 4.02 ft Ans.
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