3. The torque due to a force Facting at a displacement from the axis of rotation is given by +=xF. The force is at oriented 110⁰ cow from +x and is oriented at 60° from +x. Determine the magnitude and direction of the torque. 20N VL L... 3m 4. The cross product can also be determined if we know the components of the two vectors involved. The easiest way to do this is to write the cross product the determinant of a 3x3 matrix. The first row of the matrix is the unit vectors, and . The 2nd row is the components of the first vector and the 3rd row is the components of the second vector. The determinant of the 3x3 matrix can be written in terms of determinants of 2x2 matrices: Ax8= A₂ Ay A₂ =¹^ *-* **** * f +k Ax Ayl By By By By B₂ The determinant of a 2x2 matrix is the product of the diagonal terms minus the product of the off-diagonal terms. Therefore b. What is the magnitude of the torque? Ax8 = {(Ay 8z - Az8y) — ¡(AxB± − A±Bx) + Â(Ax By - AyBx) a. Let 7 = (2-3k) m and F = (5î-4ƒ- 10k)N. Determine the torque in component vector form. Don't forget to include units.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Question

3 and 4 please

3. The torque due to a force Facting at a displacement from the axis
of rotation is given by +=xF. The force is at oriented 110⁰
cow from +x and is oriented at 60° from +x. Determine the
magnitude and direction of the torque.
20N
VL L...
3m
4. The cross product can also be determined if we know the components of the two vectors involved. The easiest way
to do this is to write the cross product the determinant of a 3x3 matrix. The first row of the matrix is the unit
vectors, and . The 2nd row is the components of the first vector and the 3rd row is the components of the
second vector. The determinant of the 3x3 matrix can be written in terms of determinants of 2x2 matrices:
Ax8= A₂ Ay A₂ = ³^ 4-√2 4+** *
f
+k
Ax Ayl
By
By
By By B₂
The determinant of a 2x2 matrix is the product of the diagonal terms minus the product of the off-diagonal terms.
Therefore
b. What is the magnitude of the torque?
Ax8 = {(Ay 8z - Az8y) — ¡(AxB± − A±Bx) + Â(Ax By - AyBx)
a. Let 7 = (2-3k) m and F = (5î-4ƒ- 10k)N. Determine the torque in component vector form. Don't
forget to include units.
Transcribed Image Text:3. The torque due to a force Facting at a displacement from the axis of rotation is given by +=xF. The force is at oriented 110⁰ cow from +x and is oriented at 60° from +x. Determine the magnitude and direction of the torque. 20N VL L... 3m 4. The cross product can also be determined if we know the components of the two vectors involved. The easiest way to do this is to write the cross product the determinant of a 3x3 matrix. The first row of the matrix is the unit vectors, and . The 2nd row is the components of the first vector and the 3rd row is the components of the second vector. The determinant of the 3x3 matrix can be written in terms of determinants of 2x2 matrices: Ax8= A₂ Ay A₂ = ³^ 4-√2 4+** * f +k Ax Ayl By By By By B₂ The determinant of a 2x2 matrix is the product of the diagonal terms minus the product of the off-diagonal terms. Therefore b. What is the magnitude of the torque? Ax8 = {(Ay 8z - Az8y) — ¡(AxB± − A±Bx) + Â(Ax By - AyBx) a. Let 7 = (2-3k) m and F = (5î-4ƒ- 10k)N. Determine the torque in component vector form. Don't forget to include units.
Expert Solution
steps

Step by step

Solved in 3 steps with 3 images

Blurred answer
Knowledge Booster
Torque
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON