1. M, a solid cylinder (M=1.95 kg, R=0.119 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.670 kg mass, i.e., F = 6.573 N. Calculate the angular acceleration of the cylinder. I got 5.66×101 rad/s^2 2. If the force F of a mass m = 0.670 kg is hung from the string, find the angular acceleration of the cylinder. 3. How far does m travel downward between 0.390 s and 0.590 s after the motion begins? 4. The cylinder is changed to one with the same mass and radius, but a different
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1. M, a solid cylinder (M=1.95 kg, R=0.119 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.670 kg mass, i.e., F = 6.573 N. Calculate the
2. If the force F of a mass m = 0.670 kg is hung from the string, find the angular acceleration of the cylinder.
3. How far does m travel downward between 0.390 s and 0.590 s after the motion begins?
4. The cylinder is changed to one with the same mass and radius, but a different moment of inertia. Starting from rest, the mass now moves a distance 0.433 m in a time of 0.530 s. Find Icm of the new cylinder.
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