10/19 In the previous problem, what would the power requirement of the engine become if the parameters were a) The speed was to remain constant (zero acceleration), 86,3 kW Homework Problem the same, except: b) The angle of incline was 5°, 92.3 KW. C) The speed was 13 m/s, and ss,31 d) The car had a

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Please use the information from the first picture and the minor changes on the second (blank) page to solve A, B, C, and D

**Homework Problem**

In the previous problem, what would the power requirement of the engine become if the parameters were the same, except:

a) The speed  
b) The speed was to remain constant (zero acceleration), \(86.3 \, \text{kW}\)  
c) The angle of incline was \(5^\circ\), and \(99.3 \, \text{kW}\)  
d) The speed was \(13 \, \text{m/s}\), and \(55.3 \, \text{kW}\)  
e) The car had a mass of \(900 \, \text{kg}\)? \(85.3 \, \text{kW}\)  

(Note: Each option lists a power requirement in kilowatts based on adjusted conditions.)
Transcribed Image Text:**Homework Problem** In the previous problem, what would the power requirement of the engine become if the parameters were the same, except: a) The speed b) The speed was to remain constant (zero acceleration), \(86.3 \, \text{kW}\) c) The angle of incline was \(5^\circ\), and \(99.3 \, \text{kW}\) d) The speed was \(13 \, \text{m/s}\), and \(55.3 \, \text{kW}\) e) The car had a mass of \(900 \, \text{kg}\)? \(85.3 \, \text{kW}\) (Note: Each option lists a power requirement in kilowatts based on adjusted conditions.)
**Title: Calculating Power for a Car on an Incline**

**Date:** 10/19/23

**Problem Statement:**
A car of mass \( m \) moves up an incline of angle \( \theta \). The total resistive force as a function of its speed, \( v \), is given by:

\[ F_r = (218 + 0.70v^2) \, \text{N} \]

**Tasks:**

**a) Determine the power the engine must deliver to the wheels as a function of speed and desired acceleration, \( a \).**

*Equation:*
\[ P = F \cdot v = \frac{du}{dt} \]

- Power required for acceleration \( ma \)
- Resolving forces: \( F_x = F_{\text{app}} - mg\sin\theta - F_r = ma \)

**b) Assume the car has a mass of 1450 kg and the incline has a grade of 10°. Calculate the required engine power if the car is moving at a speed of 27 m/s with an acceleration of 1.0 m/s².**

**Solution Steps:**

1. **Diagram Analysis:**
   - **Diagram 1:** Illustrates forces acting on the car: gravitational force \( mg\sin\theta \), the applied force \( F_{\text{app}} \), resisting force \( F_r \), and frictional resistance.
   - Formulas:
     - \( F_{\text{app}} = ma + mg\sin\theta + F_r \)
     - Components along the incline:
       - \( ma = m\sin\theta \, (g \, \text{for acceleration}) \)
       - \( 218v \)
       - \( 0.70v^3 \)

2. **Power Calculations:**
   - \( \text{Power}_\text{required} \)
     - \( Mva = 39 \, \text{kW} = 52 \, \text{hp} \)
     - \( Mvg\sin\theta = 67 \, \text{kW} = 89 \, \text{hp} \) (to counteract gravitational force)
     - \( 218v = 5 \, \text{kW} = 7.9 \, \text{hp} \) (for rolling friction)
Transcribed Image Text:**Title: Calculating Power for a Car on an Incline** **Date:** 10/19/23 **Problem Statement:** A car of mass \( m \) moves up an incline of angle \( \theta \). The total resistive force as a function of its speed, \( v \), is given by: \[ F_r = (218 + 0.70v^2) \, \text{N} \] **Tasks:** **a) Determine the power the engine must deliver to the wheels as a function of speed and desired acceleration, \( a \).** *Equation:* \[ P = F \cdot v = \frac{du}{dt} \] - Power required for acceleration \( ma \) - Resolving forces: \( F_x = F_{\text{app}} - mg\sin\theta - F_r = ma \) **b) Assume the car has a mass of 1450 kg and the incline has a grade of 10°. Calculate the required engine power if the car is moving at a speed of 27 m/s with an acceleration of 1.0 m/s².** **Solution Steps:** 1. **Diagram Analysis:** - **Diagram 1:** Illustrates forces acting on the car: gravitational force \( mg\sin\theta \), the applied force \( F_{\text{app}} \), resisting force \( F_r \), and frictional resistance. - Formulas: - \( F_{\text{app}} = ma + mg\sin\theta + F_r \) - Components along the incline: - \( ma = m\sin\theta \, (g \, \text{for acceleration}) \) - \( 218v \) - \( 0.70v^3 \) 2. **Power Calculations:** - \( \text{Power}_\text{required} \) - \( Mva = 39 \, \text{kW} = 52 \, \text{hp} \) - \( Mvg\sin\theta = 67 \, \text{kW} = 89 \, \text{hp} \) (to counteract gravitational force) - \( 218v = 5 \, \text{kW} = 7.9 \, \text{hp} \) (for rolling friction)
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