10+139.393. The angle . The long chord of a compound is equal to 250 m. The PC this curve is at STA 10+000 and P.C.C. is that the chord connecting the P.C. and P.C.C. makes with the tangent passing through P.C. is equal to 40. Assuming that the common tangent is parallel to the long chord. a. Compute R1 ans. 998.329m b. Compute R2 ans. 639.516m c. Determine the station of P.I. of the compound curve. ans 10+140.484
10+139.393. The angle . The long chord of a compound is equal to 250 m. The PC this curve is at STA 10+000 and P.C.C. is that the chord connecting the P.C. and P.C.C. makes with the tangent passing through P.C. is equal to 40. Assuming that the common tangent is parallel to the long chord. a. Compute R1 ans. 998.329m b. Compute R2 ans. 639.516m c. Determine the station of P.I. of the compound curve. ans 10+140.484
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![1. The long chord of a compound is equal to 250 m. The PC this curve is at STA 10+000 and P.C.C. is at 10+139.393. The angle
that the chord connecting the P.C. and P.C.C. makes with the tangent passing through P.C. is equal to 40. Assuming that the
common tangent is parallel to the long chord.
a. Compute R1 ans. 998.329m
b. Compute R2 ans. 639.516m
c. Determine the station of P.I. of the compound curve. ans 10+140.484](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbe43f7c4-d1f1-4bbb-81cd-b168891bb8d2%2F15577614-fd9a-4c64-87ca-f857d0a7803a%2Fjubr51p_processed.png&w=3840&q=75)
Transcribed Image Text:1. The long chord of a compound is equal to 250 m. The PC this curve is at STA 10+000 and P.C.C. is at 10+139.393. The angle
that the chord connecting the P.C. and P.C.C. makes with the tangent passing through P.C. is equal to 40. Assuming that the
common tangent is parallel to the long chord.
a. Compute R1 ans. 998.329m
b. Compute R2 ans. 639.516m
c. Determine the station of P.I. of the compound curve. ans 10+140.484
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