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100 91 107 80 (0. 60 40 20 M*= 166 40 80 120 160 200 m/e Fig. 1 1. Fig. I contains the 70 eV electron impact mass spectrum of a compound whose combustion analysis was found to be: Carbon, 72.26 %; Hydrogen, 8.49 %. Deduce with empirical formula, the molecular formula and calculate the degree of unsaturation. How would you confirm that the Molecular Ion had indeed a value of 166? % of base peak

100 91 107 80 (0. 60 40 20 M*= 166 40 80 120 160 200 m/e Fig. 1 1. Fig. I contains the 70 eV electron impact mass spectrum of a compound whose combustion analysis was found to be: Carbon, 72.26 %; Hydrogen, 8.49 %. Deduce with empirical formula, the molecular formula and calculate the degree of unsaturation. How would you confirm that the Molecular Ion had indeed a value of 166? % of base peak

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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100 91 107 80 (0. 60 40 M*= 166 20 40 80 120 160 200 m/e Fig. 1 1. Fig. I contains the 70 eV electron impact mass spectrum of a compound whose combustion analysis was found to be: Carbon, 72.26 %; Hydrogen, 8.49 %. Deduce with empirical formula, the molecular formula and calculate the degree of unsaturation. How would you confirm that the Molecular Ion had indeed a value of 166? % of base peak
Transcribed Image Text:100 91 107 80 (0. 60 40 M*= 166 20 40 80 120 160 200 m/e Fig. 1 1. Fig. I contains the 70 eV electron impact mass spectrum of a compound whose combustion analysis was found to be: Carbon, 72.26 %; Hydrogen, 8.49 %. Deduce with empirical formula, the molecular formula and calculate the degree of unsaturation. How would you confirm that the Molecular Ion had indeed a value of 166? % of base peak
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