10.46 For Pb(NO3),, the fraction of Pb²+ ions that associate with NO, ions to form ion pairs is known to be 1 – a = 0.43 in a 0.100-mol/kg aqueous solution at 25°C. (a) Calculate I, of this solution. Note that the ion pair is charged. (b) Use the Davies equation to calculate y+ for this solution. Then calcu- late y. The experimental y is 0.395.
10.46 For Pb(NO3),, the fraction of Pb²+ ions that associate with NO, ions to form ion pairs is known to be 1 – a = 0.43 in a 0.100-mol/kg aqueous solution at 25°C. (a) Calculate I, of this solution. Note that the ion pair is charged. (b) Use the Davies equation to calculate y+ for this solution. Then calcu- late y. The experimental y is 0.395.
Chapter9: Acids, Bases, And Salts
Section: Chapter Questions
Problem 9.107E
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Question
![10.46 For Pb(NO3),, the fraction of Pb²+ ions that associate
with NO, ions to form ion pairs is known to be 1 – a = 0.43
in a 0.100-mol/kg aqueous solution at 25°C. (a) Calculate I,
this solution. Note that the ion pair is charged. (b) Use the
Davies equation to calculate y+ for this solution. Then calcu-
late y. The experimental y is 0.395.
of](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd2261535-b22f-4f2a-9f40-f811197d27df%2Fbdd9e612-9788-443d-bfae-cdaddec6b759%2F2lt0qbq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:10.46 For Pb(NO3),, the fraction of Pb²+ ions that associate
with NO, ions to form ion pairs is known to be 1 – a = 0.43
in a 0.100-mol/kg aqueous solution at 25°C. (a) Calculate I,
this solution. Note that the ion pair is charged. (b) Use the
Davies equation to calculate y+ for this solution. Then calcu-
late y. The experimental y is 0.395.
of
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