10.27 Interpret the results about the hypothesis testing of tw proportions: a. Comment if the null hypothesis should be rejected at 0.05 lev of significance when the p-value was calculated as 0.047. b. Comment if the null hypothesis should be rejected at 0.01 lev of significance when the p-value was calculated as 0.023.
Q: Test the claim that the mean GPA of night students is smaller than 2.5 at the .05 significance…
A:
Q: Assume a significance level of a = 0.05 and use the given information to complete parts (a) and (b)…
A: As per the given information, the original claim is " Less than 45% of adults would erase all of…
Q: A coach believes that her volleyball team is more athletic than the average volleyball team in…
A: Solution: μo= 100 Population mean of volleyball team in America
Q: The "Freshman 15" refers to the belief that college students gain 15 lb (or 6.8 kg) during their…
A: Since you have posted a question with multiple sub parts, we will provide the solution only to the…
Q: Assume a significance level of a = 0.05 and use the given information to complete parts (a) and (b)…
A:
Q: n a study of the accuracy of fast food drive-through orders, one restaurant had 36 orders that were…
A:
Q: Test the claim that the mean GPA of night students is larger than 2.8 at the 0.05 significance…
A: Claim : The mean GPA of night students is larger than 2.8, i.e. μ > 2.8 Hypothesis : H0 : μ = 2.8…
Q: The average student loan debt is reported to be $25,235. A student belives that the student loan…
A:
Q: One study, based on responses from 1,019 randomly selected teenagers, concluded that 41% of…
A: According to the given information in this question We need find the test statistic and p value and…
Q: Test the claim that the mean GPA of night students is significantly different than 2.1 at the 0.01…
A: Given Population mean μ=2.1, level of significance ɑ=0.01
Q: ses from One study, based on gers cite grades as their greatest source of pressure. Use a 0.05…
A: first of all we have to construct null and alternative hypotheses as follows we know that null…
Q: Carry out a test of hypothesis to draw conclusions in relation to each of the following problems. 1.…
A: Given: x=65n=100 The majority of the students are happy and contented with the universities…
Q: Assume a significance level of a = 0.05 and use the given information to complete parts (a) and (b)…
A: p=51%, p value=0.1687, level of significance ɑ=0.05
Q: Christina, a restaurant manager, would like to make the claim that the average number of customers…
A: Christina reject or fail to reject the null hypothesis is obtained below:From the information, the…
Q: Test the claim that the proportion of people who own cats is smaller than 70% at the .01…
A:
Q: Test the claim that the mean GPA of night students is significantly different than 2.4 at the 0.02…
A: Here we want to test the claim that mean GPA of night students is significantly different than 2.4…
Q: A consumer advocate conducted a hypothesis test at the 5% significance level to determine if the…
A:
Q: BELEID Identify the null and alternative hypotheses for this test. Choose the correct answer below.…
A: Given data sample size, n =100 population proportion,p= 0.24 Significance…
Q: Assume a significance level of a = 0.05 and use the given information to complete parts (a) and (b)…
A: Decision rule: If P-value is less than or equal to significance level, reject the null hypothesis.…
Q: Test the claim that the proportion of people who own cats is smaller than 90% at the 0.025…
A: Solution: The given claim is that the proportion of people who own cats is smaller than 90%.
Q: The test statistic of z = 1.20 is obtained when testing the claim that p> 0.3. a. Identify the…
A: If the alternative hypothesis contains : 1) greater than (> ) symbol then the test is right…
Q: was selected and each was weighed. The resulting readings we as follows: 100.5 90.0 91.2 96.9 96.5…
A: a. Consider that μ defines the population mean weight.
Q: Assume a significance level of a = 0.05 and use the given information to complete parts (a) and (b)…
A: Given: α=0.05P-value=0.0452Claim: p<0.47
Q: The P-value for a hypothesis test is 0.068. For each of the following significance levels, decide…
A: Given: P value=0.068 If the p-value is less than or equal to the significance level (a), we can…
Q: Assume a significance level of α=0.05 and use the given information to complete parts (a) and (b)…
A: From the provided information, Level of significance (α) = 0.05 The hypotheses can be constructed…
Q: A janitor at a large office building believes that his supply of light bulbs has a defect rate that…
A: We have given that The defect rate p = 0.09 Significance level = 0.01 The null and alternative…
Q: ind the nypolnesis les with the standardized test statistic z. Decide whether to reject HO for the…
A:
Q: Jacqueline, a medical researcher, would like to make the claim that a newly developed prescription…
A: Rejection rule:
Q: Assume a significance level of α = 0.05 and use the given information to complete parts (a) and (b)…
A: p value=0.2764,p=0.42, level of significance ɑ=0.05
Q: Test the claim that the mean GPA of night students is smaller than 2.7 at the 0.05 significance…
A: Let μ be the population mean GPA of night students. The claim is that the mean GPA of ight students…
Q: Assume a significance level of a=0.05 and use the given information to complete parts (a) and (b)…
A: a. In hypothesis testing we reject the null hypothesis if p-value < level of significance Here ,…
Q: State your decision to the significance test in terms of the null hypothesis.According to a recent…
A: The given test claims that the percentage of people in New York who would vote for the incumbent…
Q: A janitor at a large office building believes that his supply of light bulbs has a defect rate that…
A: The level of significance is the fixed probability of false elimination of the true null hypothesis…
Q: Test the claim that the mean GPA of night students is significantly different than 2.5 at the 0.01…
A: Solution This test is Two tailed test
Q: Perform the following hypothesis test: HO: µ = 6 H1: µ 6 The sample mean is 5.8, sample standard…
A:
Q: Assume a significance level of a = 0.05 and use the given information to complete parts (a) and (b)…
A:
Q: 8.72 Given M = 88, M2 = 83, ty = 2.042, t = 2.040, and a two-tailed test %3D %3D %3D %3! with a =…
A: Given M=88, M2=83, tcv= tcritical =2.042 , t=2.04=test statistic Two tailed hypothesis Level of…
Q: Jacqueline, a medical researcher, would like to make the claim that a newly developed prescription…
A: Note:Hey there! Thank you for the question. As the graph attached with your question is in an image…
Q: Assume a significance level of a = 0.05 and use the given information to complete parts (a) and (b)…
A:
Q: Test the claim that the mean GPA of night students is smaller than 2.1 at the .005 significance…
A: Consider that μ is the population mean GPA of night students.
Q: Consider the following hypothesis test: Ho: µ= 16 Ha: p # 16 A sample of 50 provided a sample mean…
A: Hey there! Thank you for posting the question. Since your question has more than 3 parts, we are…
Q: Test the claim that the mean GPA of night students is significantly different than 2.3 at the 0.1…
A:
Q: Assume a significance level of a = 0.05 and use the given information to complete parts (a) and (b)…
A: Given that, Original claim: More than 54% of adults would erase all of their personal information…
Q: Test the claim that the proportion of people who own cats is significantly different than 30% at the…
A: Z= p^-pp(1-p)n
Q: Assume a significance level of a = 0.05 and use the given information to complete parts (a) and (b)…
A:
Q: Ho: μ = 17 Ha: # 17 A sample of 50 provided a sample mean of 14.37. The population standard…
A: Given that Sample size n =50 Sample mean =14.37 Population standard deviation =6
Step by step
Solved in 2 steps with 1 images
- Assume a significance level of a = 0.05 and use the given information to complete parts (a) and (b) below. Original claim: Less than 46% of adults would erase all of their personal information online if they could. The hypothesis test results in a P-value of 0.1652. a. State a conclusion about the null hypothesis. (Reject H, or fail to reject Ho.) Choose the correct answer below. O A. Fail to reject Ho because the P-value is less than or equal to a. O B. Reject Ho because the P-value is greater than a. O C. Fail to reject H, because the P-value is greater than a. O D. Reject H, because the P-value is less than or equal to a. b. Without using technical terms, state a final conclusion that addresses the original claim. Which of the following is the correct conclusion? O A. The percentage of adults that would erase all of their personal information online if they could is more than or equal to 46%. O B. There is sufficient evidence to support the claim that the percentage of adults that…Under what circumstances is a t statistic used instead of a z-score for a hypothesis test? Justin wants to know whether a commonly prescribed drug does improve the attention span of students with attention deficit disorder (ADD). He knows that the mean attention span for students with ADD who are not taking the drug is 2.3 minutes long. His sample of 12 students taking the drug yielded a mean of 4.6 minutes. Justin can find no information regarding σx , so he calculated s2x =1.96. Identify the independent and dependent variables. In a sentence, state the null hypothesis being tested. c. Using symbols, state the null and alternative hypothesesAssume a significance level of a = 0.05 and use the given information to complete parts (a) and (b) below. Original claim: More than 55% of adults would erase all of their personal information online if they could. The hypothesis test results in a P-value of 0.2616. a. State a conclusion about the null hypothesis. (Reject H, or fail to reject Hn.) Choose the correct answer below. O A. Reject H, because the P-value is less than or equal to a. O B. Reject H, because the P-value is greater than a. OC. Fail to reject H, because the P-value is greater than a. O D. Fail to reject H, because the P-value is less than or equal to a. b. Without using technical terms, state a final conclusion that addresses the original claim. Which of the following is the correct conclusion? O A. There is not sufficient evidence to support the claim that the percentage of adults that would erase all of their personal information online if they could is more than 55%. O B. There is sufficient evidence to support…
- The test statistic of z = 2.47 is obtained when testing the claim that p > 0.8. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. Find the P-value. Using a significance level of a = 0.05, should we reject Ho or should we fail to reject Ho? A. Fail to reject Ho. There is not sufficient evidence to support the claim that p > 0.8. B. Reject Ho. There is not sufficient evidence to support the claim that p > 0.8 C. Fail to reject Ho. There is sufficient evidence to support the claim that p > 0.8. D. Reject Ho. There is sufficient evidence to support the claim that p > 0.8.For a certain hypothesis test, the computed z-value is 2.98 while the critical z-value is 2.33. The corresponding p-value for this test is A. Lesser than the significance level. B. Greater than the significance level. C. Equal to the significance level.Test the claim that the proportion of men who own cats is significantly different than 70% at the 0.1 significance level.The null and alternative hypothesis would be: a.) H0:p=0.7H0:p=0.7H1:p≠0.7H1:p≠0.7 b.)H0:μ=0.7H0:μ=0.7H1:μ>0.7H1:μ>0.7 C.) H0:μ=0.7H0:μ=0.7H1:μ<0.7H1:μ<0.7 D.) H0:μ=0.7H0:μ=0.7H1:μ≠0.7H1:μ≠0.7 E.) H0:p=0.7H0:p=0.7H1:p>0.7H1:p>0.7 F.) H0:p=0.7H0:p=0.7H1:p<0.7H1:p<0.7 The test is: A.)two-tailed B.)right-tailed C.)left-tailed Based on a sample of 30 people, 61% owned catsThe test statistic is: (to 2 decimals) = The positive critical value is: (to 2 decimals)=Based on this we: a.)Fail to reject the null hypothesis B.)Reject the null hypothesis
- Consider the following hypothesis test: H0: 4 = 15 Ha: H# 15 A sample of 50 provided a sample mean of 14.28. The population standard deviation is 7. a. Compute the value of the test statistic (to 2 decimals). (1f answer is negative, use minus "." sign.) -1.02 b. What is the p-value (to 4 decimals)? 0.3077 c. Using a = .05, can it be concluded that the population mean is not equal to 157 No Answer the next three questions using the critical value approach. d. Using a = .05, what are the critical values for the test statistic (to 2 decimals)? 1.96 e. State the rejection rule: Reject Ho if z is less than the lower critical value and is greater than the upper critical value. f. Can it be concluded that the population mean is not equal to 157 NoThe test statistic of z=1.75 is obtained when testing the claim that p≠0.432. a. Identify the hypothesis test as being two-tailed, left-tailed, or right- tailed. b. Find the P-value. c. Using a significance level of α=0.05, should we reject H0 or should we fail to reject H0? A. This is a___ test. B. P-values=____ C. What is the correct conclusion? Reject H0 or Fail to reject H0?For the given scenario, determine the type of error that was made, if any. (Hint: Begin by determining the null and alternative hypotheses.) Researchers state 2.5 hours as the mean amount of television watched by children per night. One parent claims that the mean amount of television watched by children per night is less than 2.5 hours. The parent conducts a hypothesis test and fails to reject the null hypothesis. Assume that in reality, the mean amount of television watched by children per night is 2.3 hours. Was an error made? If so, what type?
- In the past, the mean lifetime for a certain type of flashlight battery has been 9.5 hours. The manufacturer has introduced a change in the production method and wants to perform a significance test to determine whether the mean lifetime has increased as a result. The hypotheses are: null: μ = 9.5 hours alternative: u 9.5 hours Suppose that the results of a significance test result in a rejection of the null hypothesis. If we later find out that the true population running time was actually equal to 10.5, what error has been committed? Type I and Type II error Type II error no error Type I errorUse the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). The test statistic in a two-tailed test is z=1.95. A. 0.9744; fail to reject the null hypothesis B. 0.0512; fail to reject the null hypothesis C. 0.0512; reject the null hypothesis D. 0.0256; reject the null hypothesisAssume a significance level of α = 0.05 and use the given information to complete parts (a) and (b) below. Original claim: Less than 44% of adults would erase all of their personal information online if they could. The hypothesis test results in a P-value of 0.2897. a. State conclusion about the null hypothesis. (Reject Ho or fail to reject Ho.) Choose the correct answer below. O A. Fail to reject H, because the P-value is less than or equal to a OB. Reject H, because the P-value greater than a. OC. Fail to reject Ho because the P-value is greater than a O D. Reject H, because the P-value is less than or equal to a. G