10.000 3.0 m's 8000 Z 6000 Cart A 4000 2000 0.000s 0.0010 0.0015 Cart A with a mass of 2.0 kg travels at a constant speed of 3.0 m to the right on a horizontal surface, as shown in the figure. Cart A then collides with cart B with a mass of 1.5 kg that is initially at rest. The force F exerted on cart B by cart A as a function of time t is shown in the graph, where t = 0 s is the instant of initial contact between the carts. As a result of the collision, cart B moves to the right with a speed of 3.2 m. All frictional forces are considered to be negligible. A student must determine the final speed and direction of cart A and considers using the following equations. Equation 1: Ap= FÅt Equation 2: ΣΡΟΣ , Identify and justify which equation or equations the student can use. Only equation 1, because the momentum lost by cart A is gained by (A cart B. This change in momentum can be determined using the graph. Only equation 2, because the force is exerted only on cart B, so there is no B information about the force exerted on cart A. Equation 1 and equation 2, because the system is closed and all quantities are known except for the final speed of cart А. Neither equation, because there are too many unknown quantities.

10.000 3.0 m's 8000 Z 6000 Cart A 4000 2000 0.000s 0.0010 0.0015 Cart A with a mass of 2.0 kg travels at a constant speed of 3.0 m to the right on a horizontal surface, as shown in the figure. Cart A then collides with cart B with a mass of 1.5 kg that is initially at rest. The force F exerted on cart B by cart A as a function of time t is shown in the graph, where t = 0 s is the instant of initial contact between the carts. As a result of the collision, cart B moves to the right with a speed of 3.2 m. All frictional forces are considered to be negligible. A student must determine the final speed and direction of cart A and considers using the following equations. Equation 1: Ap= FÅt Equation 2: ΣΡΟΣ , Identify and justify which equation or equations the student can use. Only equation 1, because the momentum lost by cart A is gained by (A cart B. This change in momentum can be determined using the graph. Only equation 2, because the force is exerted only on cart B, so there is no B information about the force exerted on cart A. Equation 1 and equation 2, because the system is closed and all quantities are known except for the final speed of cart А. Neither equation, because there are too many unknown quantities.

Name: 10.0003.0 m/s8000Z 6000Cart A4000-0.0005 0.0010 0.0015Cart A with a m
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Description: 10.0003.0 m/s8000Z 6000Cart A4000-0.0005 0.0010 0.0015Cart A with a mass of 2.0 kg travels at a constantspeed of 3.0 m to the right on a horizontal surface, asshown in the figure. Cart A then collides with cart B witha mass of 1.5 kg that is initial

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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