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10. The combustion of methanol is described by the following equation: CH3OH + O2 → CO2 + 2H2O Use Hess's Law to calculate the enthalpy of combustion (AHC) of methanol given the following standard enthalpies of formation (AHP). OHP methanol =- 2380Kl/mol AHO H2O =-285.5 k I/mol AHP CO2 = - 393.51 kl/mol AHO O2 = 0k/mol

10. The combustion of methanol is described by the following equation: CH3OH + O2 → CO2 + 2H2O Use Hess's Law to calculate the enthalpy of combustion (AHC) of methanol given the following standard enthalpies of formation (AHP). OHP methanol =- 2380Kl/mol AHO H2O =-285.5 k I/mol AHP CO2 = - 393.51 kl/mol AHO O2 = 0k/mol

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
Section: Chapter Questions
Problem 58PS: Use standard enthalpies of formation in Appendix L to calculate enthalpy changes for the following:...
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Please answer numbers 10 and 12. Thank You!
12. If AS is calculated to be positive, there is greater disorder in the which would drive the reaction in the direction. a, reactant(s), forward b. product(s), reverse C. product(s), forward d. reactant(s), reverse
Transcribed Image Text:12. If AS is calculated to be positive, there is greater disorder in the which would drive the reaction in the direction. a, reactant(s), forward b. product(s), reverse C. product(s), forward d. reactant(s), reverse
10. The combustion of methanol is described by the following equation: CH3OH + O2 → CO2 + 2H2O Use Hess's Law to calculate the enthalpy of combustion (AHC) of methanol given the following standard enthalpies of formation (AHP). AHP methanol = - 238.0 kJ/mol AHP H2O = - 285.5 kJ/mol AHP CO2 = - 393.51 kJ/mol AHP O2 = 0 kJ/mol a. -1203.2 kJ/mol b. -441.35 kJ/mol c. 727.2 kJ/mol d. -727.2 kJ/mol
Transcribed Image Text:10. The combustion of methanol is described by the following equation: CH3OH + O2 → CO2 + 2H2O Use Hess's Law to calculate the enthalpy of combustion (AHC) of methanol given the following standard enthalpies of formation (AHP). AHP methanol = - 238.0 kJ/mol AHP H2O = - 285.5 kJ/mol AHP CO2 = - 393.51 kJ/mol AHP O2 = 0 kJ/mol a. -1203.2 kJ/mol b. -441.35 kJ/mol c. 727.2 kJ/mol d. -727.2 kJ/mol
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