10. The combustion of methanol is described by the following equation: CH3OH + O2 → CO2 + 2H2O Use Hess's Law to calculate the enthalpy of combustion (AHC) of methanol given the following standard enthalpies of formation (AHP). OHP methanol =- 2380Kl/mol AHO H2O =-285.5 k I/mol AHP CO2 = - 393.51 kl/mol AHO O2 = 0k/mol

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Please answer numbers 10 and 12. Thank You!
12. If AS is calculated to be positive, there is greater disorder in the
which would drive the reaction in
the
direction.
a, reactant(s), forward
b. product(s), reverse
C. product(s), forward
d. reactant(s), reverse
Transcribed Image Text:12. If AS is calculated to be positive, there is greater disorder in the which would drive the reaction in the direction. a, reactant(s), forward b. product(s), reverse C. product(s), forward d. reactant(s), reverse
10. The combustion of methanol is described by the following equation: CH3OH + O2 → CO2 + 2H2O
Use Hess's Law to calculate the enthalpy of combustion (AHC) of methanol given the following standard
enthalpies of formation (AHP).
AHP methanol = - 238.0 kJ/mol AHP H2O = - 285.5 kJ/mol
AHP CO2 = - 393.51 kJ/mol
AHP O2 = 0 kJ/mol
a. -1203.2 kJ/mol
b. -441.35 kJ/mol
c. 727.2 kJ/mol
d. -727.2 kJ/mol
Transcribed Image Text:10. The combustion of methanol is described by the following equation: CH3OH + O2 → CO2 + 2H2O Use Hess's Law to calculate the enthalpy of combustion (AHC) of methanol given the following standard enthalpies of formation (AHP). AHP methanol = - 238.0 kJ/mol AHP H2O = - 285.5 kJ/mol AHP CO2 = - 393.51 kJ/mol AHP O2 = 0 kJ/mol a. -1203.2 kJ/mol b. -441.35 kJ/mol c. 727.2 kJ/mol d. -727.2 kJ/mol
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