10. The combustion of methanol is described by the following equation: CH3OH + O2 → CO2 + 2H2O Use Hess's Law to calculate the enthalpy of combustion (AHC) of methanol given the following standard enthalpies of formation (AHP). OHP methanol =- 2380Kl/mol AHO H2O =-285.5 k I/mol AHP CO2 = - 393.51 kl/mol AHO O2 = 0k/mol
10. The combustion of methanol is described by the following equation: CH3OH + O2 → CO2 + 2H2O Use Hess's Law to calculate the enthalpy of combustion (AHC) of methanol given the following standard enthalpies of formation (AHP). OHP methanol =- 2380Kl/mol AHO H2O =-285.5 k I/mol AHP CO2 = - 393.51 kl/mol AHO O2 = 0k/mol
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please answer numbers 10 and 12. Thank You!
![12. If AS is calculated to be positive, there is greater disorder in the
which would drive the reaction in
the
direction.
a, reactant(s), forward
b. product(s), reverse
C. product(s), forward
d. reactant(s), reverse](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9183b805-9289-4c56-a2f9-caa9d7c4280c%2Fa9e8921c-eb81-47b1-a207-6d532507fcc7%2Feco489n_processed.jpeg&w=3840&q=75)
Transcribed Image Text:12. If AS is calculated to be positive, there is greater disorder in the
which would drive the reaction in
the
direction.
a, reactant(s), forward
b. product(s), reverse
C. product(s), forward
d. reactant(s), reverse
![10. The combustion of methanol is described by the following equation: CH3OH + O2 → CO2 + 2H2O
Use Hess's Law to calculate the enthalpy of combustion (AHC) of methanol given the following standard
enthalpies of formation (AHP).
AHP methanol = - 238.0 kJ/mol AHP H2O = - 285.5 kJ/mol
AHP CO2 = - 393.51 kJ/mol
AHP O2 = 0 kJ/mol
a. -1203.2 kJ/mol
b. -441.35 kJ/mol
c. 727.2 kJ/mol
d. -727.2 kJ/mol](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9183b805-9289-4c56-a2f9-caa9d7c4280c%2Fa9e8921c-eb81-47b1-a207-6d532507fcc7%2Fcu0cr5q_processed.jpeg&w=3840&q=75)
Transcribed Image Text:10. The combustion of methanol is described by the following equation: CH3OH + O2 → CO2 + 2H2O
Use Hess's Law to calculate the enthalpy of combustion (AHC) of methanol given the following standard
enthalpies of formation (AHP).
AHP methanol = - 238.0 kJ/mol AHP H2O = - 285.5 kJ/mol
AHP CO2 = - 393.51 kJ/mol
AHP O2 = 0 kJ/mol
a. -1203.2 kJ/mol
b. -441.35 kJ/mol
c. 727.2 kJ/mol
d. -727.2 kJ/mol
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