10. At room temperature, the equilibrium constant, Keq is approximately 3. Calculate the number of moles of reactants and products expected in the equilibrium mixture of this reaction. (Hint: Complete the ICE table

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wt of flask = 98.4669

wt of product = 20.7868

wt of flask and product = 119.2537

weight of water collected = 4.4 mL

wt of water expected 4.5 mL 

percent yeild of ester = 71.58%

19.0 mL of 0.25 M n-propanol

18.5 mL propionic acid

 

plz answer questions below

10. At room temperature, the equilibrium constant, Keq is approximately 3. Calculate the number of moles of
reactants and products expected in the equilibrium mixture of this reaction. (Hint: Complete the ICE table
below. Let X be the number of moles of each product formed at equilibrium. Substitute into the equilibrium
equation using the moles of each reactant and product at equilibrium, each divided by the total reaction
volume. Leave the equilibrium concentrations as fractions. Solve for X. You can then take the square root of
both sides of the equation after cancelling like terms, i.e. the volumes.)
Acid
Alcohol +
Ester
H20
Initial amount
(.25/V)
(.25/V)
Change
At Equilibrium
11. What would the % yield of ester be if the reaction were simply allowed to equilibrate (i.e. no products are
removed)?
12. Compare your experimental % yield of n-propyl propanoate to the predicted equilibrium yield. Were you
successful in driving the reaction to the right?
Transcribed Image Text:10. At room temperature, the equilibrium constant, Keq is approximately 3. Calculate the number of moles of reactants and products expected in the equilibrium mixture of this reaction. (Hint: Complete the ICE table below. Let X be the number of moles of each product formed at equilibrium. Substitute into the equilibrium equation using the moles of each reactant and product at equilibrium, each divided by the total reaction volume. Leave the equilibrium concentrations as fractions. Solve for X. You can then take the square root of both sides of the equation after cancelling like terms, i.e. the volumes.) Acid Alcohol + Ester H20 Initial amount (.25/V) (.25/V) Change At Equilibrium 11. What would the % yield of ester be if the reaction were simply allowed to equilibrate (i.e. no products are removed)? 12. Compare your experimental % yield of n-propyl propanoate to the predicted equilibrium yield. Were you successful in driving the reaction to the right?
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