10. A printer manufacturing company claims that itsnew ink-efficient printer can print an average of1500 pages of words documents with standarddeviation of 60. Thirty-five (35) of these printersshowed a mean of 1475 pages. Does this supportthe company's claim? Use 0.05% level ofsignificance.Formulate the Null Hypothesis Test andAlternative Hypothesis Test.Ho: µ = 1500 Ha: µ = 1500Ho: µ = 1475 Ha: u z 1475Ho: p = 1500 Ha: p > 1500Ho: µ = 1500 Ha: µ < 150011. It is a decision making process for evaluatingclaims about a population based on thecharacteristics of a sample purportedly comingfrom that population.Null Hypothesis TestAlternative Hypothesis TestHypothesis TestTailed Test12. A printer manufacturing company claims that itsnew ink-efficient printer can print an average of1500 pages of words documents with standarddeviation of 60. Thirty-five (35) of these printersshowed a mean of 1475 pages. Does this supportthe company's claim? Use 0.05% level ofsignificance.What is the decision?Ho is accepted and Ha is rejectedHo is rejected and Ha is rejectedHo is rejected and Ha is acceptedHo is accepted and Ha is accepted

We have given the following statement about Hypothesis testing. Note: According to Bartleby expert…

Answered: 10. A printer manufacturing company…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Bone mineral density (BMD) is a measure of bone strength. Studies show that BMD declines after age 45. The impact of exercise may increase BMD. A random sample of 59 women between the ages of 41 and 45 with no major health problems were studied. The women were classified into one of two groups based upon their level of exercise activity: walking women and sedentary women. The 39 women who walked regularly had a mean BMD of 5.96 with a standard deviation of 1.22. The 20 women who are sedentary had a mean BMD of 4.41 with a standard deviation of 1.02. Which of the following inference procedures could be used to estimate the difference in the mean BMD for these two types of women
2. A pain reliever currently being used in a hospital is known to bring relief in a mean time of 3.5 minutes. To compare a new pain reliever with the one currently being used, a random sample of 45 patients is given the new drug. The mean time to relief for this sample is 2.8 minutes with a standard deviation of 1.14 minutes. a) Test the research (alternative) hypothesis that the new drug is more effective than the old drug, using α ≤ .05. b) Assuming a standard deviation of 1.14 minutes, approximately how large a sample of patients would be needed to form a 90% confidence interval to estimate the population time-to-relief of the new drug accurate to within plus or minus 10 seconds? Answers: 2. a) Z = -4.12, reject H0, new drug is more effective, b) 127
6. An automatic Coffee dispenser is advertised to pour u=16 oz of coffee with a standard deviation of o-0.1 oz. An unsatisfied customer wants to know if the automatic Coffee dispenser pours less than 16 oz on average. A random sample of n=49 cups of coffee is taken and is found to have a sample mean x = 15.96 oz. Use a a-5% level of significance to test if the population mean u is less than 16 oz. a) State the null and alternate hypothesis. b) Find the test statistic (either z or t). c) Find the p-value or sketch the critical region. d) State whether you will reject or fail to reject the null
Suppose two food preservatives are extensively tested and determined safe for use in meats. A processor wants to compare the preservatives for their effects on retarding spoilage. Suppose 16 cuts of fresh meat are treated with preservative A with mean 95.25 and Sample standard deviation 13.45. And another 12 cuts of meat are treated with preservative B with mean 100.50 and standard deviation 10.55. The number of hours until spoilage begins is recorded for each of the 28 cuts of meat. The value of the test statistic for determining if there is a difference in the population variances for preservatives A and B is equal to: A. 1.129. OB. 1.275. OC. 1.625. OD. 0.784.
9) Steel rods are manufactured with a mean length of 25 centimeters (cm). Because of variability in the manufacturing process, the lengths of the rods are approximately normally distributed, with a standard deviation of 0.07 cm. What proportion of rods has a length less than 24.9 cm? b. C. d. 25 Any rods that are shorter than 24.85 cm or longer than 25.15 cm are discarded. What proportion of rods will be discarded? Using the results of part (b), if 5,000 rods are manufactured in a day, how many should the plant manager expect to discard? If an order comes in for 10,000 steel rods, how many rods should the plant manager manufacture if the order states that all rods must be between 24.9 cm and 25.1 cm?
5. ERP Companyis a company that produces Brand A toothpaste and uses a machine to package 250 grams per tube. Assume that the net weight is normally distributed with a population standard deviation of 10 grams. A randomly selected 45 tubes of Brand A toothpaste have a mean weight of 255 grams. Is the packaging machine functioning properly? Test the claim ?=250grams at 0.05 level of significance.
Please answer the last three parts of this question.
The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $14,124. The following year, a random sample of 20 two-year institutions had a mean of $17,124 and a standard deviation of $3700. Is there sufficient evidence at the alpha level of 0.05 to conclude that the mean cost has increased. Show 6 steps of hypothesis
2) The manufacturer of a certain brand of automobiles component claims that mean life of these component is 70 months. An independent agency wants to check this claim and took a random sample of 40 components and found that the mean life for this sample is 67 months with a standard deviation of 5 months. At 5% LOS, can we conclude that the mean life of these component is less than 70 months?
8. A company claims that rechargeable batteries it produces can last at least 50,000 hours. A randomly selected 40 batteries had a mean of 49,000 hours. It is assumed that the battery life is normally distributed with a standard deviation of 5,800 hours. Conduct an appropriate hypothesis test using the critical value approach, at the 0.05 level of significance. Is there evidence that the mean battery life as claimed by the company is true?

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