10. A +2.8% grade at 1 + 200 is to be connected to a -4.2% grade at 1+600 using a symmetrical parabolic curve. The tangents intersect at elevation 178.53m. Compute the distance of the highest point from BVC. a) 200 m c) 160 m b) 240 m d) 178.53 m 11. A +2.8% grade at 1 + 200 is to be connected to a -4.2% grade at 1+600 using a symmetrical parabolic curve. What is the vertical distance of Pl from BVC? a) 4.8 m c) 2.8 m b) 5.6 m d) 8.4 m

Q: For vertical alignment with one equal tangent vertical curve where g1 = -5%, g2 = +7%, L = 300.00…

A: Vertical alignment is the alignment of a pipe in the vertical direction with respect to the required…

Q: 3. For curve y + 4x2 - 12x , locate the possible maximum and minimum %D points.

A:

Q: A 160m long parabolic curve connects a -8% grade to a +2% grade. These grades intersect at Sta.…

A:

Q: 23.15 A +4% grade intersects a -3% grade at station 3+ 000m at elevation 566.98 m. Compute the…

A: PVCSTATION=PVISTA-L2PVCsta=3000-6002=2+700PVCELV=PVIELV-g1L2PVCelv=566.98-0.04×6002PVCelv=554.98m

Q: A +3 % grade @ PC intersects with a -4.2 % grade at PI forming a symmetrical vertical curve with…

A:

Q: An asymmetrical vertical parabolic curve has a forward descending grade of 4% and backward ascending…

A:

Q: 3. A grade of +5% grade intersects a grade of -3.0% P.C. has a of 10 + 110.00 which has an elevation…

A:

Q: A - 6% grade and a + 2% grade intersect at sta. 12 + 200 whose elevation is at 45.673 m. The two…

A: PVCELV=PVIELV-g1L2PVCelv=45.673+0.06×1802PVCelv=51.073m

Q: vertical parabolic curve of length 180m has he following specifications. The point of teraction of…

A:

Q: Q6. A -2.5% grade is connected to a +1.0% grade by means of a 180 m vertical curve. The P.I. station…

A:

Q: A downgrade of 4.6° meets an upgrade of 3.20% at Sta . 73+108 where the elevation is 998 m. A…

A: Given; downgrade = 4.6°  Sta = 73+108 elevation = 998 m. parabolic curve AB=440 m long

Q: Given two grades intersecting at station 1 + 250m, one grade at +6%, the other at -3%. Use a…

A: Given data, Two grade intersecting at station 1+250m g1=+6% and g2=-3% L=183m L1=121.95m and…

Q: A -4% grade at Sta. 5 + 700 and elev. 110.2 is to connect to a +6% grade at Sta. 6 + 100 and elev.…

A: G1 = -4%  , BVC, station = 5+700  ,  elevation = 110.2                            G1 = +6% , EVC,…

Q: curve has a length of 141m with tangent grades of -1.5% and 2.5% intersecting at station 12+640.22…

A: PVCSTATION=PVISTA-L2PVCsta=12640.22-1412=12+569.72PVCELV=PVIELV-g1L2PVCelv=240-0.025×1412PVCelv=238.…

Q: A vertical parabolic curve passes thru point A whose elevation is 23.23 m at a distance of 54 meters…

A: Find grade of forward tangent

Q: A grade descending at the rate of -4% intersects another grade ascending at the rate of +8% at…

A: We have to determine the value of necessary length of the curve as per the given data in the…

Q: A 6.2% grade is followed by -2.8% grade; the grades intersecting at sta. 10+800 of elevation 1060 m…

A: The grades are g1=6.2% and g2=-2.8%. The station of grade intersection is PVI=10+800. The elevation…

Q: elevation is 23.23 m at a distance of 54 meters from the point of curvature. The elevation of the…

A: Given:- elevation=23.23m d=54m elevation at point of curvature=22.56m Station 4+100m grade of back…

Q: forward tangent is -3.0%, and the location of the highest point elevation of the highest point is…

A:

Q: A 669m equal tangent crest vertical curve has PVC at Sta 18+662 and at elevation 199m. The initial…

A: Given- PVCSTA=18+662E=199mn1=7.25%n2=-7.42%L=669m

Q: A 3% ascending grade meets a 5% descending grade at station 2+110 and elevation 100m. The tangents…

A:

Q: A parabolic curve has a descending grade of -0.85% which meets an ascending grade of 0.35% at sta.…

A: Given Data: A parabolic curve is given as: Descending grade(g1)=-0.85%Ascending…

Q: A -6% grade is followed by a 2% grade intersecting at Sta. 15+750, with an elevation of 372.25 m.…

A:

Q: A -2.6% grade meets a +4.8% grade near an underpass. To maintain the minimum clearance allowed under…

A:

Q: A -4% grade at Sta. 5 + 700 and elev. 110.2 is to connect to a +6% grade at Sta. 6 + 100 and elev.…

A: Determine the elevation of PCC and location of PVI.

Q: tangent is -3.0%, and the location of the highes on of the highest point is 100 m. t is the Station…

A:

Q: 12. A sag curve is composed of two parabolic curves. BVC and EVC have elevations 250.30m and 246.30m…

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Q: -3% grade is connected to a +1.2% grade by means of 200 m vertical curve. The PJ station is 100+ 00…

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Q: A-2.4% grade meets a +7.4% grade at a vertex (El. 142.68m) directly under an overpass bridge having…

A:

Q: Q3:- A parabolic vertical curve joins a grade of -3% to a grade of +5.5 %. The PVI is at station…

A: The downward gradient (g1) = -3% = -0.03   The upward gradient (g2) = +5.5% = 0.055The station of…

Q: 3. A level 0.0 percent grade (g₁) intersects a plus 5.0 percent grade (g₂) at station (kilometer)…

A: Grade 1, g1=0.0 % Grade 2, g2=5.0 % Station in kilometer, 1+000 Elevation of station = +80.00 Length…

Q: 7. A -3% grade meets a +5% grade near an underpass. In order to maintain the minimum clearance…

A: jkjethgnfjhjjj

Q: A 175m long sag parabolic curve connects a -8.2% grade to a +2.4% grade. The grades intersect at…

A:

Advanced Framing Techniques

In construction engineering, framing means joining together pieces of members to build a whole structure. Framing is the step where the construction project starts taking its shape. Wood, engineered wood, and structural steel are some of the framing materials used in construction. The framing technique is divided into two types, lightweight framing, and heavyweight framing. In the heavyweight framing, the vertical supports are few, and the size and weight of the pieces to be used are more like timber framing, pole building framing, and steel framing. Lightweight framing has several smaller size vertical pieces like a balloon, platform, and light-steel framing.