10. (8 pts) A molecule with formula C15H24 has the proton NMR spectrum shown below. Draw structure in the box provided and include any reasoning for partial credit. Singlet, 3H Septet, 3H Doublet, 18H 8 7 6 5 4 3 2 0 PPM partial credit: benzene ring 1 pt, iPr that does not couple 1 pt
10. (8 pts) A molecule with formula C15H24 has the proton NMR spectrum shown below. Draw structure in the box provided and include any reasoning for partial credit. Singlet, 3H Septet, 3H Doublet, 18H 8 7 6 5 4 3 2 0 PPM partial credit: benzene ring 1 pt, iPr that does not couple 1 pt
Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
ChapterL4: Proton (1h) Nmr Spectroscopy
Section: Chapter Questions
Problem 12E
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please help me solve these both questions by explaining the pieces that forms at each peak and the final structure for my
![10. (8 pts) A molecule with formula C15H24 has the proton NMR spectrum shown below. Draw
structure in the box provided and include any reasoning for partial credit.
Singlet, 3H
Septet, 3H
Doublet, 18H
8
7
6
5
4
3
2
0
PPM
partial credit: benzene ring 1 pt, iPr that does not couple 1 pt](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa17c26d4-84f8-4179-865a-162c145f6c44%2F32b3e548-85f2-44ef-af40-f21de4e4497e%2Fba7bhht_processed.jpeg&w=3840&q=75)
Transcribed Image Text:10. (8 pts) A molecule with formula C15H24 has the proton NMR spectrum shown below. Draw
structure in the box provided and include any reasoning for partial credit.
Singlet, 3H
Septet, 3H
Doublet, 18H
8
7
6
5
4
3
2
0
PPM
partial credit: benzene ring 1 pt, iPr that does not couple 1 pt
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