10 Q1 is the following model a probability model P(x) 123 + 4 In the given model, the probabilities associated with the outcomes 1, 2, and 4 are 0.35, 0.4, and 0.3, respectively. These probabilities are all between O and 1, satisfying the first criterion. However, the probability associated with the outcome 3 is -0.05, which is less than 0. This violates the first criterion, so the model is not a probability model. Additionally, the sum of the probabilities of all possible outcomes is 0.35 0.4+ (-0.05 + 0.3 = 1, satisfying the second criterion. However, since the first criterion is not met, the model is not a probability model. Q2 0.35+0.5-0.2=0.65 Q3 P(e)=0.65 0.35 0.4 -0.05 0.3 Find P(E or F) if p(e)=0.35, p(f)=0.5 p(e and f)=0.2 Find the probability p(e) if p(e)=0.35
10 Q1 is the following model a probability model P(x) 123 + 4 In the given model, the probabilities associated with the outcomes 1, 2, and 4 are 0.35, 0.4, and 0.3, respectively. These probabilities are all between O and 1, satisfying the first criterion. However, the probability associated with the outcome 3 is -0.05, which is less than 0. This violates the first criterion, so the model is not a probability model. Additionally, the sum of the probabilities of all possible outcomes is 0.35 0.4+ (-0.05 + 0.3 = 1, satisfying the second criterion. However, since the first criterion is not met, the model is not a probability model. Q2 0.35+0.5-0.2=0.65 Q3 P(e)=0.65 0.35 0.4 -0.05 0.3 Find P(E or F) if p(e)=0.35, p(f)=0.5 p(e and f)=0.2 Find the probability p(e) if p(e)=0.35
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Transcribed Image Text:10
Q1
is the following model a probability model
P(x)
123 +
4
In the given model, the
probabilities associated
with the outcomes 1, 2,
and
4 are 0.35, 0.4, and 0.3,
respectively.
These probabilities are all
between O and 1,
satisfying the first
criterion.
However, the probability
associated with the
outcome 3 is -0.05, which
is less than 0. This violates
the first criterion, so the
model is not a probability
model.
Additionally, the sum of
the probabilities of all
possible outcomes is
0.35 0.4+ (-0.05 + 0.3
=
1, satisfying the second
criterion.
However, since the first
criterion is not met, the
model is not a probability
model.
Q2
0.35+0.5-0.2=0.65
Q3
P(e)=0.65
0.35
0.4
-0.05
0.3
Find P(E or F) if p(e)=0.35, p(f)=0.5 p(e and f)=0.2
Find the probability p(e) if p(e)=0.35
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