10 mL of 0.100 M Sn2+ was titrated with 0.1000 M Ce4+ to give the redox products, Sn4+ and Ce3+ in 0.10 M HCl. What is the potential after the addition of 10 mL of the titrant? standard reduction potential Sn4+/Sn2+ = 0.15 V Ce4+/Ce3+ = 1.44 V

Q: X(s)|X1+ (1.37 M) || Mn O4 1 minus (1.85 M)|Mn2+ (0.75 M)|H+ (1.94 M) The reduction potential for…

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Q: Complete the table. Calculate the cell potential when 20.0 mL of 0.05 M Fe2+ was titrated with 0.05…

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Q: A voltaic cell is constructed in which the cathode is a standard hydrogen electrode and the anode is…

A: Given data, Pressure of H2 at anode = 1 atm Cell potential = 0.221 V Temperature = 298 K

Q: Given: Cr3+(aq) + 3e– ----> Cr(s); E° = –0.74 V Ag+(aq) + e–   --------> Ag(s); E° = 0.80 V What…

A: Answer:

Q: X(s)|X3+ (2.04 M) || Mn O4 1 minus (1.62 M)|Mn2+ (0.25 M)|H+ (2.64 M) The reduction potential for…

A: Given   The concentration of X3+ is 2.04 M. The concentration of MnO4- is 1.62 M. The concentration…

Q: X(s)|X1+ (2.33 M) || Mn O4 1 minus (0.93 M)|Mn2+ (0.91 M)|H+ (1.82 M) The reduction potential for…

A: Nernst equation: The Nernst equation relates to the reduction potential of an electrochemical…

Q: At 25ºC, you conduct a titration of 20.00 mL of a 0.0400 M AgNo3 solution with a 0.050 M NaI soution…

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Q: Consider the following cell: Cu(s) | CuCl2(0.065 M) || FeCl2(0.035 M) | Fe(s) a) Using the standard…

A: a) Reduction half cell reaction ( Cathode): Fe2++2e-→Fe    Ecell=-0.45 Oxidation half cell reaction…

Q: At 25 C, a titration of 15.00 mL of a 0.0560 M AgNO, solution with a 0.0280 M Nal solution is…

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Q: A voltaic cell is constructed in which the cathode is a standard hydrogen electrode and the anode is…

A: Given Ecell = 0.233V Ecell = - RTnFln [H+]0.233= - 8.314 x2981 x 96500ln [H+]- 9.075 = ln [H+] [H+]…

Q: The standard reduction potential of the zinc cation is -0.76 V. The measured cell potential for the…

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Q: X(s)|X3+ (1.81 M) || Mn O4 1 minus (2.14 M)|Mn2+ (1.83 M)|H+ (1.98 M) The reduction potential for…

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Q: The electrochemical cell: SCE||H+ (a=x)|glass electrode has a potential of 0.2094 V when the…

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Q: The cell potential for this reaction is, V when [ Zn2*] = 1.0 M and [Pb2*] = 2.0 x 10-4 M. Pb2+ (aq)…

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Q: The standard reduction potential of Cu(s) is + 0.339 V. What is its standard oxidation potential?…

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Q: Cr3+(aq) + 3e– -> Cr(s); E° = –0.74 V Ag+(aq) + e– -> Ag(s); E° = 0.80 V What is the cell…

A: We will use nernest Equation

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Q: The concentration of NO3- in a water sample was determined using ion-selective electrode. A 25.00 mL…

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Q: X(s)|X1+ (0.99 M) || Mn O4 1 minus (0.18 M)|Mn2+ (1.90 M)|H+ (2.64 M) The reduction potential for…

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Q: X(s)|X2+ (1.09 M) || Mn O4 1 minus (2.56 M)|Mn2+ (0.72 M)|H+ (0.22 M) The reduction potential for…

A: The cell given is, => X(s)|X2+ (1.09 M) || MnO4- (2.56 M)|Mn2+ (0.72 M)|H+ (0.22 M) In the above…

Q: Chloride ions are added to the Ag|Ag+ half-cell of the cell Ag|Ag+||Cu2+|Cu to precipitate AgCl (s).…

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Q: X(s)|X4+ (0.87 M) || Mn O4 1 minus (1.61 M)|Mn2+ (2.98 M)|H+ (1.49 M) The reduction potential for…

A: Given information: Reduction potential for X4+ = 2.22 V Reduction potential for MnO4- = 1.51 V

Q: X(s)|X4+ (2.75 M) || Mn O4 1 minus (2.58 M)|Mn2+ (2.75 M)|H+ (0.30 M) The reduction potential for…

A: According to the cell diagram given,Anode is at left side to salt bridge and cathode is at right…

Q: X(s)|X3+ (1.14 M) || Mn O4 1 minus (1.97 M)|Mn2+ (0.64 M)|H+ (2.79 M) The reduction potential for…

A: Given data,EoX3+/X=0.46VEoMnO4-/Mn2+=1.51VX(s)|X3+ (1.14 M) || MnO4- (1.97 M)|Mn2+(0.64 M)|H+ (2.79…

Q: At 25 °C, a titration of 15.00 mL of a 0.0560 M AgNO3 solution with a 0.0280 M Nal solution is…

A:

Q: The standard reduction potential of the zinc cation is -0.76 V. The measured cell potential for the…

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Q: The cell potential of the following cell at 25°C is 0.475 V: Zn|Zn?+ (0.20 M) || H* (test…

A: The given cell is, Therefore,

Q: Mn(k) | Mn²+(0.2 M) || H+ (pH= ?) | H2 (g, 1.5 atm) | The cell potential of the Pt(k) Cell was found…

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Q: The cell potential of the following cell at 25°C is 0.475 V: Zn|Zn?t (1.0 M) || H* (test solution)…

A: