3. Estimate Eº for the half-reaction 2H₂O + 2e → H₂ + 2OH* given the following values of AG : H₂O(l) = -237 kJ/mol H₂(g) = 0.0 OH(aq) = -157 kJ/mol e = 0.0 Compare this value of E° with the value of E° given in Table 18.1
3. Estimate Eº for the half-reaction 2H₂O + 2e → H₂ + 2OH* given the following values of AG : H₂O(l) = -237 kJ/mol H₂(g) = 0.0 OH(aq) = -157 kJ/mol e = 0.0 Compare this value of E° with the value of E° given in Table 18.1
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:3. Estimate Eº for the half-reaction
2H₂O + 2e → H₂ + 2OH-
given the following values of AG :
H₂O(l) = -237 kJ/mol
H₂(g) = 0.0
OH(aq) = -157 kJ/mol
e = 0.0
Compare this value of E° with the value of E° given in Table 18.1

Transcribed Image Text:3' Ž Standard Reduction Potentials at 25°C (298 K) for Many Common Half-Reactions
Half-Reaction
F₂+2e-2F
Ag+ e → Ag
coi te co
H₂O₂ + 2H+ 2e → 2H₂O
Ce +e→Ce"
PbO₂ + 4H+SO+2e →PbSO. + 2H₂O
MnO, + 4H+ + 3e →MnO₂ + 2H₂O
2e + 2H+10 →10 + H₂O
MnO, +8H + 5e →Mn² + 4H₂O
Au + 3e → Au
PbO₂ + 4H+ 2e →Pb² + 2H₂O
Cl₂ +2e2C1-
Cr₂0,² + 14H+ + 6e →2Cr³+ + 7H₂0
O₂ + 4H+ 4e → 2H₂O
MnO₂ + 4H+ + 2e →Mn²+ + 2H₂O
10₂ + 6H + 5e →→₂ + 3H₂O
Br₂ +2e2Br
VO₂ + 2H+ e→VO² + H₂O
AuCl₂ + 3e-Au + 4C
NO₂ + 4H+ 3e→NO + 2H₂O
CIO₂ + e→CIO,
2Hg2+ 2e → Hg₂²⁰
Ag+ e → Ag
Hg₂+ 2e →→ 2Hg
Fe +eFe²+
O₂ + 2H+ 2e → H₂O₂
MnO, + e→→MnO²-
1₂ + 2e → 21-
Cut + e-Cu
8° (V)
2.87
1.99
1.82
1.78
1.70
1.69
1.68
1.60
1.51
1.50
1.46
1.36
1.33
1.23
1.21
1.20
1.09
1.00
0.99
0.96
0.954
0.91
0.80
0.80
0.77
0.68
0.56
0.54
0.52
Half-Reaction
O₂ + 2H₂O + 4e →40H™
Cu²+ 2e → Cu
Hg,Cl₂ + 2e → 2Hg + 2C1-
AgCl+eAg + Cr
SO2 + 4H+ 2e → H₂SO₂ + H₂O
Cu²+eCut
2H + 2e → H₂
Fe + 3e-Fe
Pb²+ + 2e →→ Pb
Sn² +2e → Sn
Ni²+ + 2e-Ni
PbSO4 + 2e →→ Pb + 50,²
Cd²+2e →→ Cd
Fe + 2e → Fe
Cr³+ + e→Cr³
Cr³+ + 3e-Cr
Zn²+2e → Zn
2H₂O + 2e →→H₂ + 20H™
Mn +2e →→Mn
AP+3e Al
H₂ + 2e → 2H™
Mg2+2e → Mg
La" + 3e-La
Na + e-Na
Ca²+2e →→ Ca
Ba²+2e-Ba
K' + e-K
Li' + e-Li
gº (V)
0.40
0.34
0.34
0.22
0.20
0.16
0.00
-0.036
<-0.13
<-0.14
-0.23
<<-0.35
-0.40
-0.44
-0.50
-0.73
-0.76
-0.83
-1.18
-1.66
-2.23
-2.37
-2.37
<-2.71
-2.76
-2.90
-2.92
-3.05
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