10 Mg(s) + Cd(aq) -> Mg (aq) + Cd(s) E = +1.98 V The magnesium electrode was dipped into a 1.00 M salution of M9SO4 and the cadmium elestrede was dipped into a solution of unknown Cd* concentration. The pctential of the cell was measured to be +1.54 V. What was the unknown Cd? concentration? (Answer: 1.4 x 1015 M)
10 Mg(s) + Cd(aq) -> Mg (aq) + Cd(s) E = +1.98 V The magnesium electrode was dipped into a 1.00 M salution of M9SO4 and the cadmium elestrede was dipped into a solution of unknown Cd* concentration. The pctential of the cell was measured to be +1.54 V. What was the unknown Cd? concentration? (Answer: 1.4 x 1015 M)
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![10 Mg(s) + Cd(aq) -> Mg (aq) + Cd(s)
E = +1.98 V
The magnesium electrode was dipped into a 1.00 M salution of M9SO4 and the cadmium
ele:trede was dipped into a solution of unknown Cd* concentration. The pctentlal of the
cell was measured to be +1.54 V. What was the unknown Cd? concentration?
(Answer : 1.4 x 1015 M)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2b2285b8-a2a6-4f81-b102-07f1e9e11a1f%2Fd9ebb250-c2d3-4dbe-9365-64d1caa58b75%2Fv20i6f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:10 Mg(s) + Cd(aq) -> Mg (aq) + Cd(s)
E = +1.98 V
The magnesium electrode was dipped into a 1.00 M salution of M9SO4 and the cadmium
ele:trede was dipped into a solution of unknown Cd* concentration. The pctentlal of the
cell was measured to be +1.54 V. What was the unknown Cd? concentration?
(Answer : 1.4 x 1015 M)
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