When the Pb2 concentration is 1.01 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 2.340V. What is the Mg2+ concentration? Pb2*(aq) + Mg(s)→ Pb(s) + Mg²*(aq) Answer: M When the Cu2+ concentration is 7.90×10 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 1.902V. What is the AIt concentration? 3Cu²*(aq) + 2AI(s)–3Cu(s) + 2A³*(aq) Answer: M
When the Pb2 concentration is 1.01 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 2.340V. What is the Mg2+ concentration? Pb2*(aq) + Mg(s)→ Pb(s) + Mg²*(aq) Answer: M When the Cu2+ concentration is 7.90×10 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 1.902V. What is the AIt concentration? 3Cu²*(aq) + 2AI(s)–3Cu(s) + 2A³*(aq) Answer: M
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please answer both A and B.
Standard reduction potentials are given.

Transcribed Image Text:Standard Reduction (Electrode) Potentials at 25 °C
Standard Reduction (Electrode) Potentials at 25 °C
Half-Cell Reaction
E° (volts)
Half-Cell Reaction
E° (volts)
Hg22 (aq) + 2 e →2 Hg(l)
0.789
F2(g) + 2 e → 2 F'(aq)
2.87
Fe (aq) + e¯ Fe2*(aq)
0.771
Ce (aq) + e¯ →Ce³*(aq)
1.61
L(s) + 2 e 2 I'(aq)
0.535
MnO4 (aq) + 8 H*(aq)+ 5 e¯ → Mn²*(aq) + 4 H,O(1)
1.51
Fe(CN), (aq) + e Fe(CN),+(aq)
0.48
Cl2(g) + 2 e¯ –→2 CI(aq)
1.36
Cu2+(aq) + 2 e → Cu(s)
0.337
Cr20,2 (aq) + 14 H*(aq) + 6 e¯ → 2 Cr³*(aq) + 7 H2O(1)
Cu2*(aq) + e¯ –→ Cu*(aq)
1.33
0.153
O2(g) +4 H*(aq) + 4 e¯ →2 H0(1)
S(s) + 2 H*(aq) + 2 e¯ →H2S(aq)
1.229
0.14
Br2(1) + 2 e¨ –→ 2 Br°(aq)
1.08
2 H (aq) + 2 e¯ →H2(g)
0.0000
NO3 (aq) + 4 H (aq) + 3 e¯ → NO(g) + 2 H2O(1)
Pb2t
*(aq) + 2 e¯ → Pb(s)
0.96
-0.126
2 Hg2*(aq) + 2 e →Hg2²*(aq)
Sn2*(aq) + 2 e → Sn(s)
-0.14
0.920
Hg"(aq) + 2 e" →Hg(1)
Ni2*(aq) + 2 e → Ni(s)
-0.25
0.855
Ag (aq) + e –Ag(s)
Co2*(aq) + 2 e¯ →Co(s)
-0.28
0.799
Hg2 (aq) + 2 e → 2 Hg(1)
Cd2*(aq) + 2 e¯ –→ Cd(s)
-0.403
0.789
Cr*(aq) + e¯ → Cr*(aq)
-0.41
Fe3*(aq) + e¯ → Fe²*(aq)
0.771
Fe2*(aq) + 2 e¯ – Fe(s)
-0.44
I2(s) + 2 e → 2 I'(aq)
0.535
Cr*(aq) + 3 e¯ – Cr(s)
-0.74
Fe(CN)6 (aq) + e Fe(CN)6*(aq)
0.48
-0.763
Zn2*(aq) + 2 e¯ – Zn(s)
Cu2*(aq) + 2 e¯ →Cu(s)
0.337
-0.83
H,O(1) + 2 e¯ –H2(g)+ 2 OH´(aq)
Lo153.
2 H20(1) + 2 e →H2(g)+2 OH´(aq)
-0.83
Mn2*(aq) + 2 e
→ Mn(s)
-1.18
-1.66
Al3*(aq) + 3 e –→ Al(s)
Mg²*(aq) + 2 e¯ → Mg(s)
-2.37
-2.714
Na (aq) + e¯ → Na(s)
-2.925
K*(aq) + e¯ → K(s)
-3.045
Li (aq) + e → Li(s)

Transcribed Image Text:When the Pb2+ concentration is 1.01 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 2.340V. What is
the Mg2+
concentration?
Pb²*(aq) + Mg(s) Pb(s) + Mg²*(aq)
Answer:
M
When the Cu²+ concentration is 7.90×10 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 1.902V.
What is the AIt concentration?
3Cu²*(aq) + 2Al(s)3Cu(s) + 2AF*(aq)
Answer:
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