EO = 0.59 V, E = -3.04 V Mn02 Mn04- Li I) Calculate AG° (kJ/mol) for the following electrochemical cell II) If the cell emf of a Li-MnO, cell is 3.64 V when the concentration of Li* is 0.5 M, what is the concentration of MnO, ? Li(s) | Li*(aq)(0.5 M) || MnOg(aq)(? M)| MnO2(s) O AG° = -709 kj/mol, [MnO,] = 0.6 M O AG° = -709 kj/mol, [MnO] = 0.4 M AG° = -1051 kj/mol, [MnO,] = 0.6 M AG° = -1051 kj/mol, [MnO] = 0.4 M none of the above

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Electrochemistry

E0
Mn02
0.59 V, Eº,
i = -3.04 V
Mn04-
Li+
I) Calculate AG° (kJ/mol) for the following electrochemical cell
II) If the cell emf of a Li-MnO, cell is 3.64 V when the concentration of Li* is 0.5 M, what is the
concentration of MnO4 ?
Li(s) | Li*(aq)(0.5 M) || MNO4(aq)(? M)| MnO2(s)
AG° = -709 kj|mol, [MnO,] = 0.6 M
AG° = -709 kj|mol, [MnO,] = 0.4 M
AG° = -1051 kj/mol, [MnO,] = 0.6 M
AG° = -1051 kj/mol, [MnO,] = 0.4 M
none of the above
Transcribed Image Text:E0 Mn02 0.59 V, Eº, i = -3.04 V Mn04- Li+ I) Calculate AG° (kJ/mol) for the following electrochemical cell II) If the cell emf of a Li-MnO, cell is 3.64 V when the concentration of Li* is 0.5 M, what is the concentration of MnO4 ? Li(s) | Li*(aq)(0.5 M) || MNO4(aq)(? M)| MnO2(s) AG° = -709 kj|mol, [MnO,] = 0.6 M AG° = -709 kj|mol, [MnO,] = 0.4 M AG° = -1051 kj/mol, [MnO,] = 0.6 M AG° = -1051 kj/mol, [MnO,] = 0.4 M none of the above
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