10-16. A 1 m cube within a mass of stressed soil has a stress of 100 kPa on its top and bottom faces, 50 kPa on one pair of vertical faces, and 30 kPa on the other pair of vertical faces. There is no shear stress on any face. Fill in the numerical values for each stress and angle in the following table. (After Taylor, 1948.) Major principal plane: Intermediate principal plane: Minor principal plane: o(kPa) T(kPa) α

10-16. A 1 m cube within a mass of stressed soil has a stress of 100 kPa on its top and bottom faces, 50 kPa on one pair of vertical faces, and 30 kPa on the other pair of vertical faces. There is no shear stress on any face. Fill in the numerical values for each stress and angle in the following table. (After Taylor, 1948.) Major principal plane: Intermediate principal plane: Minor principal plane: o(kPa) T(kPa) α

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.

Question

10-16. A 1 m cube within a mass of stressed soil has a stress of 100 kPa on
its top and bottom faces, 50 kPa on one pair of vertical faces, and
30 kPa on the other pair of vertical faces. There is no shear stress
on any face. Fill in the numerical values for each stress and angle in
the following table. (After Taylor, 1948.)
o(kPa)
7(kPa)
a
Major principal plane:
Intermediate principal plane:
Minor principal plane:
Plane of maximum shearing stress:
Plane of maximum obliquity:
Note: a is with respect to the horizontal plane.

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Limiting states 1. The MC describes the state of stress of our point in the field. That is, the MC shows us the values of the two principal stresses and the value of the maximum shear stress that the point is sustaining in the field. Consider a point in a geostatic soil mass. For our point, o'vo = 100 kPa and o'ho = 40 kPa. Take a sheet of paper and draw the Mohr Circle for this point carefully. 2. Now, we know that o'ho is a principal stress because t = 0 on the vertical plane (in the field). Similarly, o'vo is a principal stress because t = 0 on the horizontal plane (in the field). What is the value of t on the plane inclined 45 degrees clockwise from the horizontal? Go ahead and use your drawn MC to find this value. The value should be t = 30 kPa. 3. Note that the value found (t = 30 kPa) is the maximum shear stress that the point is supporting in the field, as it is under o'v = 100 kPa and o'h = 40 kPa. Consider now a situation in which o'h remains at 40 kPa, but o'y grows to 120…