1.What reagent is used as the indicator for the neutralization?
a)citric acid
b)sodium hydroxide
c)sodium citrate
d)phenolphthalein
2.
What is the mole ratio of NaOH to citric acid for this neutralization reaction?
a)2 mole NaOH/1 mole citric acid
b)1 mole NaOH/1 mole citric acid
c)1 mole NaOH/2 mole citric acid
d)1 mole NaOH/3 mole citric acid
e)3 mole NaOH/1 mole citric acid
3.If 35.00 mL of 0.1104 M NaOH were used to reach the neutralization point, how many moles of NaOH were dispensed?
a)3.154 x 10-3 mol NaOH
b)1.104 x 10-4 mol NaOH
c)258.8 mol NaOH
d)3.864 x 10-3 mol NaOH
4. Using the above mole ratio, convert the moles of NaOH in the previous question to moles of citric acid.
a)1.288 x 10-3 mol citric acid
b)1.159 x 10-2 mol citric acid
c)3.864 x 10-3 mol citric acid
d)1.932 x 10-3 mol citric acid
5.
How many grams of citric acid were neutralized in the question above? (MM = 192.12 g/mol)
a)0.7425 g citric acid
b)0.2475 g citric acid
c)0.0825 g citric acid
d)6.704 x 10-6 g citric acid
These are my answers
1. I think it's d (phenolphthalein)
2. I think it's e ( 3:1)
3. I think it's e
4. I don't know
5. I don't know
If you could double check my answers for #1-3 that would be great! But most importanly if you could help with 4-5 because I am very confused on those. I have also included a picture of my lab beucase these are pre-lab qustions, but I don't think you'll need it. Thank you so much
Trending now
This is a popular solution!
Step by step
Solved in 3 steps