1.16 Ti(a) transforms to Ti(B) at 882°C (1155 K), with a heat of transforma- tion equal to 830 cal/mole (3,473 J/mol). Calculate the heat of reaction when Ti(B) is oxidized by pure oxygen gas to form Ti0, at 1400°c (1673 K). The First Law of Thermodynamics 27 Given: Ti(a) + Ti02i AHO 298 = -225.5 kcal/mole (-943.49 kJ/mol). Cp,Ti(c) 5.28 + 2.4 x 10 T cal/deg/mole (22.09 + 10.04 X 10° T J/K/mol). CP,Ti(B) 6.91 cal/deg/mole (28.91 J/K/mol). 18.0 + 0.28 x 10° T - 4.35 x 10° 1 cal/deg/mole T - 18.2 x 10 Cp,Ti02 (75, 31 + 1.17 x 103 J/K/mol). 7.16 + 1.0 x 10 3 T - 0.4 x 10 T2 Cp,O2 cal/deg/mole J/K/mol). (29. 96 + 4,184 x 103 T - 1.67 X 10° "-2

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1.16 Ti(a) transforms to Ti(B) at 882°C (1155 K), with a heat of transforma-
tion equal
to 830 cal/mole (3,473 J/mol).
Calculate the heat of reaction
when Ti(B) is oxidized by pure oxygen gas to form Ti0, at 1400°C (1673 K).
The First Law of Thermodynamics
27
Given:
Ti(a) +
Ti02;
AHO
298
= -225.5 kcal/mole (-943.49 kJ/mol).
Cp,Ti(a)
5.28 + 2.4 x 10 T cal/deg/mole
(22.09 + 10.04 X 10° T J/K/mol).
CP,Ti(B)
6.91 cal/deg/mole (28.91 J/K/mol).
Cp,Ti02
18.0 + 0.28 x 10 T - 4.35 x 10° T cal/deg/mole
(75, 31 + 1.17 x 103
T - 18.2 x 10
J/K/mol).
Cp,02
7.16 + 1.0 x 10 T - 0.4 x 10° T
cal/deg/mole
(29. 96 + 4,184 x 103
T - 1.67 X 10° 72
J/K/mol).
Transcribed Image Text:1.16 Ti(a) transforms to Ti(B) at 882°C (1155 K), with a heat of transforma- tion equal to 830 cal/mole (3,473 J/mol). Calculate the heat of reaction when Ti(B) is oxidized by pure oxygen gas to form Ti0, at 1400°C (1673 K). The First Law of Thermodynamics 27 Given: Ti(a) + Ti02; AHO 298 = -225.5 kcal/mole (-943.49 kJ/mol). Cp,Ti(a) 5.28 + 2.4 x 10 T cal/deg/mole (22.09 + 10.04 X 10° T J/K/mol). CP,Ti(B) 6.91 cal/deg/mole (28.91 J/K/mol). Cp,Ti02 18.0 + 0.28 x 10 T - 4.35 x 10° T cal/deg/mole (75, 31 + 1.17 x 103 T - 18.2 x 10 J/K/mol). Cp,02 7.16 + 1.0 x 10 T - 0.4 x 10° T cal/deg/mole (29. 96 + 4,184 x 103 T - 1.67 X 10° 72 J/K/mol).
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