1.11 Given that P - 2a, – a, - 2a. Q = 4a, + 3a, + 2a. R - -a, + a, + 2a. find: (a) |P + Q – R|, (b) P-Q× R, (c) Q × P· R, (d) (P x Q) · (Q × R), (e) (P × Q) × (Q × R), (f) cos O pg. (g) sin Øro-

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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1.11 Given that
P - 2a, - a, – 2a.
Q = 4a, + 3a, + 2a.
R = -a, + a, + 2a.
%3D
find: (a) P + Q- R|, (b) P-Qx R, (c) Q x P R, (d) (P x Q) (Q x R),
(e) (P x Q) x (Q x R), (f) cos 0 pg. (g) sin 0po-
Transcribed Image Text:1.11 Given that P - 2a, - a, – 2a. Q = 4a, + 3a, + 2a. R = -a, + a, + 2a. %3D find: (a) P + Q- R|, (b) P-Qx R, (c) Q x P R, (d) (P x Q) (Q x R), (e) (P x Q) x (Q x R), (f) cos 0 pg. (g) sin 0po-
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