1. Write the equilibrium constant expression for each of the following reactions. a. CO3(aq) + H2O(1) HCO3(aq) + OH(aq) Keq = b. 2 KClO3(s) 2 KCI(s) + 3 O2(g) Keq = c. HF(aq) + H2O(1) H3O+ (aq) + F (aq) Keq = d. NH3(aq) + H2O(1) NH4+ (aq) + OH(aq) Keq = 2. For the reaction C(s, diamond) → C(s, graphite), AG = -2.9 kJ/mol. a. According to this information, do diamonds spontaneously turn into graphite? circle one: yes no b. In light of your answer to part (a), why can diamonds be kept unchanged for thousands of years?

Chemistry for Engineering Students
4th Edition
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Author:Lawrence S. Brown, Tom Holme
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Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.11PAE
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1. Write the equilibrium constant expression for each of the following reactions.
a. CO3(aq) + H2O(1) HCO3(aq) + OH(aq)
Keq =
b. 2 KClO3(s) 2 KCI(s) + 3 O2(g)
Keq =
c. HF(aq) + H2O(1) H3O+ (aq) + F (aq)
Keq =
d. NH3(aq) + H2O(1) NH4+ (aq) + OH(aq)
Keq =
2. For the reaction C(s, diamond) → C(s, graphite), AG = -2.9 kJ/mol.
a. According to this information, do diamonds spontaneously turn into graphite?
circle one: yes no
b. In light of your answer to part (a), why can diamonds be kept unchanged for thousands of
years?
Transcribed Image Text:1. Write the equilibrium constant expression for each of the following reactions. a. CO3(aq) + H2O(1) HCO3(aq) + OH(aq) Keq = b. 2 KClO3(s) 2 KCI(s) + 3 O2(g) Keq = c. HF(aq) + H2O(1) H3O+ (aq) + F (aq) Keq = d. NH3(aq) + H2O(1) NH4+ (aq) + OH(aq) Keq = 2. For the reaction C(s, diamond) → C(s, graphite), AG = -2.9 kJ/mol. a. According to this information, do diamonds spontaneously turn into graphite? circle one: yes no b. In light of your answer to part (a), why can diamonds be kept unchanged for thousands of years?
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