1. What torque must be applied to link 2 of the linkage illustrated in Fig. 1 to maintain static equilibrium? Assume RA02= 87.5 mm; RBA=RB04 =150 mm; Rco4=100 mm; R0204=50 mm; RD04 175 mm. D P=222.5 B 4 105.1° 240° 3 + T12 2 A 152.4° 02 04

= 3. The following data apply to a four-bar linkage similar to the one illustrated in Fig. 3: RA02 =120 mm, R0402 = 300 mm, RBA = 320 mm, RB04 = 250 mm, RCA = 360 mm, 0c = 15°, RD04 = 0, 0D = 0°, RG202 = 0, RG3A = 200 mm, α = 8°, RG404=125 mm, ẞ =0°, m2 = 0.5 kg, m3 = 4 kg, m4 =1.5 kg, IG2 = 0.005 N m s², IG3 0.011 N m s², IG4=0.0023 N m s². A kinematic analysis at 02 = 90° and 2 = 32 rad/s² ccw with α2 = 0 and gave 03 = 23.9°. 04 = 91.7º, α3 = 221 rad/s² ccw, α4 =122 rad/s² ccw, AG3 =88.6 m/s² 255°, AG4 =32.6 m/s² 244°. Using an external force Fc = 632 N Z342° acting at point C, make a complete dynamic analysis of the linkage. C УА 3 B G₁₂ 4 13 GA TA Ꭰ Do B 02 3 A 2 12 04 02 r1 X 04 Figure 3

Problem 4. For the belt drive shown below calculate the contact angle 0, if: D %3D 100 mт; d 3 30 тm; C = 300 mm. D-d 20 sin V4c² - (D – d)²- -1 D-d sin 20 Op

please answer and explain be specific and i will upvote if correct and explained