1. What are the resultant force (R) of each scenario: a) Western force of 40 N and a eastern force of 20 N, R = b) F = 201, F2 = -33ŷ, R = %3D %3D %3D c) Southern force of 50 N and a Northeast force of 50 N, R =

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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Chapter 7: PHYS 203: Fundamentals of Physics**

**Concurrent and Parallel Forces**

---

**Key Concepts:**

- **2-Dimensional Forces:**  
  \[ \vec{F} = F_x\hat{i} + F_y\hat{j} \]

- **Free Body Diagrams**

- **Torque:**  
  \[ \tau = rF \]

- **Mechanical Equilibrium:**  
  \[ \sum \vec{F} = 0 \]  
  \[ \sum \vec{\tau} = 0 \]

- **Center of Gravity**

---

**Reinforcement:**

1. **What are the resultant force \((\vec{R})\) of each scenario:**

    a) Western force of 40 N and an eastern force of 20 N, \(\vec{R} = \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \)

    b) \(F_1 = 20\hat{i}, F_2 = -33\hat{j}, \vec{R} = \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \)

    c) Southern force of 50 N and a Northeast force of 50 N, \(\vec{R} = \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \)

2. **A lug nut on a wheel of an automobile is specified to be torqued at 55.0 N·m. If the tire iron used to tighten the nut is 20.3 cm long, what is the force needed to apply to achieve the specification?**

3. **A 2500 kg truck is 5.00 m from one end of a 27.0 m long bridge. A 1500 kg car is 10.0 m from the same end. How much weight must each end of the bridge support for mechanical equilibrium to hold?**
Transcribed Image Text:**Chapter 7: PHYS 203: Fundamentals of Physics** **Concurrent and Parallel Forces** --- **Key Concepts:** - **2-Dimensional Forces:** \[ \vec{F} = F_x\hat{i} + F_y\hat{j} \] - **Free Body Diagrams** - **Torque:** \[ \tau = rF \] - **Mechanical Equilibrium:** \[ \sum \vec{F} = 0 \] \[ \sum \vec{\tau} = 0 \] - **Center of Gravity** --- **Reinforcement:** 1. **What are the resultant force \((\vec{R})\) of each scenario:** a) Western force of 40 N and an eastern force of 20 N, \(\vec{R} = \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \) b) \(F_1 = 20\hat{i}, F_2 = -33\hat{j}, \vec{R} = \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \) c) Southern force of 50 N and a Northeast force of 50 N, \(\vec{R} = \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \) 2. **A lug nut on a wheel of an automobile is specified to be torqued at 55.0 N·m. If the tire iron used to tighten the nut is 20.3 cm long, what is the force needed to apply to achieve the specification?** 3. **A 2500 kg truck is 5.00 m from one end of a 27.0 m long bridge. A 1500 kg car is 10.0 m from the same end. How much weight must each end of the bridge support for mechanical equilibrium to hold?**
Expert Solution
answer

a)R=-20N x^

b)R=20 x^-33 y^

c)R=0

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