1. We know a population has a standard deviation of 90. If a sample of 1296 people has a sample mean of 1500 then A. Construct a 90% confidence Interval B. Construct a 95% confidence Interval C. Construct a 98% confidence Interval
Q: e: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the…
A: Sample size n =47 Sample mean=109 Population standard deviation =32
Q: A survey of 81 individuals finds that the average amount they spend on entertainment each month is…
A: Given n=81, Xbar=145,s=54 We want to find 95% CI for population mean
Q: 30. Bob draws a simple random sample from an original population. The sample size is n = 51, the…
A: Given : n= 51.0 , x̄= 78.0 s= 14.0 At 95.0 % confidence level , z score= 1.96
Q: For a sample of 120 businesses, the average profit they generate in a month is $54,000 with a…
A: We have given that, Average or sample mean (x̄) = 54000, standard deviation (s) = 8800 and sample…
Q: A statistics instructor randomly selected four bags of oranges, each bag labeled 10 pounds, and…
A: From the provided information, Sample size (n) = 4 Confidence level = 95%
Q: 1. Your colleague collected a sample of data regarding the mean length of a movie and they computed…
A: It has been given that the confidence interval of the mean length of a movie has been computed on a…
Q: Given a sample size of 400 with a mean of 80 and the population standard deviation is found to be 35…
A: We have given that, Sample mean (x̄) = 80, population standard deviation (σ) = 35 and sample size…
Q: Assuming that the population is normally distributed, construct a 95% confidence interval estimate…
A: The question is about confidence intervalGiven :To find :1 ) 95 % CI estimate for the popl. mean…
Q: A. Find the confidence intervals for the population mean from the given data. 1. x = 5.8, n = 36, o…
A: as per Bartleby guideline expert have to answer first question only dear students please upload…
Q: A statistics practitioner took a random sample of 56 observations from a population whose standard…
A: We have given that, Sample size (n) = 56, population standard deviation (σ) = 35 and sample mean…
Q: sample of 40 observations is selected from a normal population where the population variance is 625.…
A: According to the given information in this questionThere are more than three subparts according to…
Q: 5. You are given the sample mean and the population standard deviation. Use this information to…
A: Given,sample size(n)=50sample mean(x¯)=$147population standard deviation(σ)=$17.20
Q: The town of KnowWearSpatial, U.S.A. operates a rubbish waste disposal facility that is overloaded if…
A:
Q: 2. Create a 97% confidence interval to estimate the mean study hours per week for a Wingate female.…
A: The sample mean is x¯=9.07 hours.The sample standard deviation is s=8.12 hoursThe sample size is…
Q: If n=12, x=47, and s=7, construct a confidence interval at a 98% confidence level. Assume the data…
A: According to the provided information,
Q: If n = 17, ¯xx¯ = 33, and s = 6, construct a confidence interval at a 99% confidence level. Assume…
A: We have, If n = 17, x¯ = 33, and s = 6, alpha=1-0.99= 0.01 Therefore Degrees of freedom= n-1=16…
Q: If n = 18, = 46, and s = 16, construct a confidence interval at a 90% confidence level. Assume the…
A:
Q: 3. You are given the sample mean and the population standard deviation. Use this information to…
A: It is given that Sample mean = 123 Population standard deviation = 15.20 Sample size = 40
Q: A statistics practitioner took a random sample of 43 Note: For each confidence interval, enter your…
A: n = 43 standard deviation = 27 mean = 104 95% confidence interval for mean is given by x±zα2*σn 104…
Q: Given a mean of 483, a standard deviation of 29, and a sample size of 60, construct a 95 %…
A: A mean of 483, a standard deviation of 29, and a sample size of 60, construct a 95% confidence…
Q: atistics practitioner took a random sample of 49 observations from a population whose standard…
A: Sample size n =49 Sample mean=103 Population standard deviation =25
Q: 13, ¤(x-bar)=39, and s=16, construct a confidence interval at a 90% confidence level. Assume the…
A: From the given information, n=13 x-bar=39 s=16 Confidence level=90% Significance level=10%…
Q: a. Find the point estimates for the population mean and the population standard deviation for the…
A: "Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…
Q: Which of the following would result in the narrower confidence interval?
A: Note: The confidence interval with small confidence level has the narrower confidence interval. The…
Q: n elephants, the mean weight of a newborn elephant is 244 pounds with a population standard…
A: Here it is given that - Number of samples (n) = 100 Mean (x¯) = 244 Standard deviation (σ) = 11
Q: You measure 37 textbooks' weights, and find they have a mean weight of 73 ounces. Assume the…
A: From the provided information, Sample size (n) = 37 Sample mean (x̅) = 73 Population standard…
Q: Suppose you have a sample of five people wher x represents cookie consumption in the past week. The…
A: Hi, we are supposed to answer three subparts at a time. Therefore, I am answering the first three…
Q: Imagine that a researcher appropriately conducts a z test and then calculates a correseponding 95%…
A:
Q: Use the information about each of the following samples to compute the confidence interval to…
A: Since you have posted a question with multiple sub parts, we will provide the solution only to the…
Q: A sociologist develops a test to measure attitudes towards public transportation, and 37 randomly…
A: given that,sample mean, x =58.5standard deviation, s =19.7sample size, n =37standard error = sd/…
Q: Suppose a random sample of 50 basketball players have an average height of 78 inches. Also assume…
A: Note: According to Bartleby expert guidelines, we can answer only first question with their three…
Q: In a survey of 2445 adults in a recent year, 1491 say they have made a New Year's resolution.…
A: From the given information, let X be the number of adults have made a New Year’s resolution. X =…
Q: Which of the following statements is correct about confidence intervals?
A: (A) Incorrect Since, on increasing the confidence level, the error bound increases. As one has to…
Q: We take a sample of 218 men and find they have an average commute time of 32 minutes with a standard…
A: Given: a sample of 218 men and find they have an average commute time of 32 minutes with a standard…
Q: According to a telephone survey of adults, 86% of homeowners said that owning a home was a good…
A: From the given information, According to a telephone survey of adults, 86% of homeowners said that…
Q: A statistics practitioner took a random sample of 59 observations from a population whose standard…
A: sample size(n)=59 Population standard deviation(σ)=32 Mean(x)=95
Q: mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use…
A: Given, n=40 Sample meanx=$138.00 Population standard deviation σ=$17.80
Q: A statistics practitioner took a random sample of 43 observations from a population whose standard…
A: We have given that, sample mean (x̄) = 109, standard deviation (σ) = 30 and sample size (n) = 43
Q: Given the following GPA for 4 students: 2, 3, 3, 4. Age of students are: 10, 11, 12, 15. There are…
A: Given Given the following GPA for 4 students: 2, 3, 3, 4. Age of students are: 10, 11,12, 15. There…
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- Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.If n=25 and the sample standard deviation is 15, construct a 95% confidence interval for the true standard deviation. (Assume the population is approximately Normal).A statistics practitioner took a random sample of 42 observations from a population whose standard deviation is 30 and computed the sample mean to be 102. Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits. A. Estimate the population mean with 95% confidence. Confidence Interval = B. Estimate the population mean with 90% confidence. Confidence Interval = C. Estimate the population mean with 99% confidence. Confidence Interval =
- 4. on paper. random sample of 130 human body temperatures had a mean 98.25 degree and astandard deviation of 0.73 degree. Construct a 99% confidence interval for the average body temperature ofhealthy people.A statistics instructor randomly selected four bags of oranges, each bag labeled 10 pounds, and weighed the bags. They weighed 10.3, 10.8, 10.4, and 10.6 pounds. Assume that the distribution of weights is Normal. Find a 95% confidence interval for the mean weight of all bags of oranges. Use technology for your calculations. Answer parts a and b below. a. Choose the correct interpretation of the confidence interval below and, if necessary, fill in the answer boxes to complete your choice. A. We are 95% confident the population mean is between and B. There is a 95% chance that all intervals will be between and C. We are 95% confident that the sample mean is between and D. The requirements for constructing a confidence interval are not satisfied. (Type integers or decimals rounded to the nearest thousandth as needed. Use ascending order.)A. You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 40 home theater systems has a mean price of $127.00. Assume the population standard deviation is $19.30. Construct a 90% confidence interval for the population mean. The 90% confidence interval is B. A study of lobster trap placement used a 95% confidence interval to estimate the mean trap spacing (in meters) for the population of red spiny lobster fishermen fishing in the west coast. How many teams of fisherman would need to be sampled in order to reduce the width of the confidence interval to 6 meters? Assume prior knowledge indicates that the trap spacing readings for the population of red spiny lobster taken during a day are approximately…
- Assume that the 95% confidence interval for mean=9 and standard devaition=20. For a particular data, the standardized value z = 2.73. We can say that: Select one: a. The data with standardized value 2.73 does not belong to the confidence interval and the value is less than the average. b. The data with standardized value 2.73 does not belong to the confidence interval and the value is greater than the average. c. Cannot interpret the z-value information provided. d. The data with standardized value 2.73 if it belongs to the confidence interval and the value is less than the average. e. The data with standardized value 2.73 if it belongs to the confidence interval and the value is greater than the average.A. Find the sample meanB. Find the sample standard deviation C. Construct a 98% confidence interval for the population mean(please show what numbers you are putting into the formula for part b)Which type of confidence interval should you use in this situation? A sample of 25 different payroll departments found that the employees worked an average of 310.3 days a year with a standard deviation of 23.8 days. The distribution is approximately normally distributed. Find the 90% confidence interval for the average days worked of all payroll departments. Question 2 options: 1) a confidence interval for the mean using a table value from the standard normal distribution. 2) a confidence interval for the mean using a table value from the t distribution. 3) a confidence interval for a proportion using a table value from the standard normal distribution. 4) a confidence interval for proportion using a table value from the t distribution. 5) none of the above.
- A statistics practitioner took a random sample of 48 observations from a population whose standard deviation is 32 and computed the sample mean to be 107. Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits. A. Estimate the population mean with 95% confidence. Confidence Interval = B. Estimate the population mean with 90% confidence. Confidence Interval = C. Estimate the population mean with 99% confidence. Confidence lInterval =A. You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 40 business days, the mean closing price of a certain stock was $107.60.Assume the population standard deviation is $10.03. The 90% confidence interval is B. A study on the personality characteristics of drug dealers sampled 100 convicted drug dealers and scored them each on the Wanting Recognition (WR) Scale, which provides a quantitative measure of a person's need for approval and sensitivity to social situations. (Higher scores indicate a greater need for approval.) The sample of drug dealers had a mean WR score of 44, with a standard deviation of 6. Use this information to find an interval estimate of the mean WR score for all convicted drug dealers. Use a confidence level of 99%. Interpret the result.…