2. Create a 97% confidence interval to estimate the meanstudy hours per week for a Wingate female. The samplemean was 9.07 hours, the sample standard deviation was8.12, and the sample size was 82. Interpret yourconfidence interval. I needed to add the females fromlast semester to the sample to bring the sample size over30 because the values did not come from a normaldistribution.

The sample mean is x¯=9.07 hours.The sample standard deviation is s=8.12 hoursThe sample size is…

Answered: 2. Create a 97% confidence interval to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Solve the following. Show your complete solution. The in-city gasoline mileage per gallon was computed for two economy automobiles, each for 40 tanks of gasoline. The mean and standard deviation of the mile per gallon readings were given in the following table. Find a 90% confidence interval for the difference in mean miles per gallon for the two automobiles. Interpret your result.
In a poll, 1100 adults in a region were asked about their online vs. in-store clothes shopping. One finding was that 44% of respondents never clothes-shop online. Find and interpret a 95% confidence interval for the proportion of all adults in the region who never clothes-shop online. Click here to view page 1 of the table of areas under the standard normal curve. Click here to view page 2 of the table of areas under the standard normal curve. The 95% confidence interval is from to (Round to three decimal places as needed.)
bcd.
This question applies to the next 3 MCQs. Wire wound resistors are being custom made for a Design House with a maximum specification of 305.70 ohms and a minimum specification of 304.55 ohms. If the resistance is higher it can be reworked, if lower they must be scrapped. The resistors manufactured follow a normal distribution with a mean of 305.2 ohms and a standard deviation of 0.25 ohms. What percentage of the resistors are scrap (approximately)? 5% 2% 0.1% 0.5% 1%
Please help with question 5 a-b
Assume that distances people driving to work are normally distributed. In a random sample of five people, the mean driving distance to work was 23 miles and the standard deviation was 6 miles. What is the length of the 95% confidence interval for the mean driving distance to work. Round to the nearest mile.
Suppose we have only ten scores representing the ages (in years) of randomly selected U.S. commercial aircraft. The average age of the ten aircraft is 14.25 years and the sample standard deviation is 9.349 years. Construct a 95% confidence interval for the mean age of all U.S. commercial aircraft. I would appreciate to see what formulas you use and the work through because I messed up.
You want to rent an unfurnished one-bedroom apartment in Durham, NCnext year. The mean monthly rent for a random sample of 60 apartmentsadvertised on Craig’s List (a website that lists apartments for rent) is$1000. Assume a population standard deviation of $200. Construct a 95%confidence interval. Duncan Jones kept careful records of the fuel efficiency of his car. Afterthe first 100 times he filled up the tank, he found the mean was 23.4 milesper gallon (mpg) with a population standard deviation of 0.9 Compute the 95 percent confidence interval for his mpg.
A random sample of 64 shoppers showed that they spend an average of $27.31 per visit at the Sunday Mornings Bookstore. The standard deviation of the population is $2.14. Find the 90% confidence interval of the true mean. Please include all work showing how you found your answer.
Last year, the average amount that teams for the Statistics Games raised was $375. Have teams been more successful at fundraising this year? To find out, you take a random sample of 36 teams. Your sample of 36 teams yields a mean of $396 and a standard deviation of $70. Might you have made a Type 1 or Type 2 error? A Type 1. This means that we said that the mean amount raised had increased, when it was actually still $375. B You might have made a calculation error. C Neither- we're sure the average has increased. D Type 2. This would mean that we said there was not enough evidence to say the mean had increased from $375, when it actually is higher than $375. E Either kind is possible!
We asked 41 people to report the number of cars they've ever owned. The results are a mean of 4.6 and a standard deviation of 1.3. Construct a 80% confidence interval.
For a group of 20 students taking a PSDTF test, the mean heart rate was 96 beats per minute, and the standard deviation was 5. Find the 95% confidence interval of the true mean.

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