1. Using the data table below regarding the coil of wire, use Equation 2 to calculate the theoretical value of the resistance, Rtheo for each of the five coils and record the results in the empty slots, also below. Copper Resistivity (m) German Silver Resistivity (22m) 1.72E-08 2.80E-07 Coill Material Resistivity (m) 1.72E-08 Length (m) 10 Diameter (m) 0.0006439 Radius (m) Area (m²) Rabo (2) Coil2 Coil3 Coil4 1.72E-08 1.72E-08 1.72E-08 10 20 20 0.0003211 0.0006439 0.0003211 Coil5 2.80E-07 10 0.0006439

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Using this equation included, may someone please help me?

1. Using the data table below regarding the coil of wire, use Equation 2 to calculate the
theoretical value of the resistance, Rtheo for each of the five coils and record the results in
the empty slots, also below.
Copper Resistivity (m)
German Silver Resistivity
(m)
1.72E-08
2.80E-07
Coill
Material Resistivity (m) 1.72E-08
Length (m)
Diameter (m)
10
Radius (m)
Area (m²)
Rho (22)
Coil2
Coil3
Coil4
Coil5
1.72E-08
1.72E-08 1.72E-08
20
2.80E-07
10
10
20
0.0006439 0.0003211 0.0006439 0.0003211 0.0006439
Transcribed Image Text:1. Using the data table below regarding the coil of wire, use Equation 2 to calculate the theoretical value of the resistance, Rtheo for each of the five coils and record the results in the empty slots, also below. Copper Resistivity (m) German Silver Resistivity (m) 1.72E-08 2.80E-07 Coill Material Resistivity (m) 1.72E-08 Length (m) Diameter (m) 10 Radius (m) Area (m²) Rho (22) Coil2 Coil3 Coil4 Coil5 1.72E-08 1.72E-08 1.72E-08 20 2.80E-07 10 10 20 0.0006439 0.0003211 0.0006439 0.0003211 0.0006439
R _ PL
A
Transcribed Image Text:R _ PL A
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