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1. Two masses are attracted by gravitational force of 0.24 N. What will the force of attraction be if the distance btwn the two masses is halved. Can you show me how to solve ?

1. Two masses are attracted by gravitational force of 0.24 N. What will the force of attraction be if the distance btwn the two masses is halved. Can you show me how to solve ?

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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So i just asked that question in the picture but at the bottom where it say F = 4F ..where did that 4 come ? I am still not quite grasping the breakdown.... please help
7:06 & O @ * 82%i 1. Two masses are attracted by gravitational force of 0.24 N. What will the force of attraction be the distance btwn the two masses is halved. Can you show me how to solve ? given: F = 0.24 N (at distance r) we have to find F'=? , at distance (r'=r/2) Step2 b) Formula Used: F = Gmlm2 p2 for distance r, 0. 24 = Gmlm2 (1) for distance r', F' = Gmlm2 p2 (2) (2) /(1) Gmlm2 F Gmlm2/r2 $ = (:)* = ()* F F' = 4F F = 4 * 0. 24 F = 0.96 N
Transcribed Image Text:7:06 & O @ * 82%i 1. Two masses are attracted by gravitational force of 0.24 N. What will the force of attraction be the distance btwn the two masses is halved. Can you show me how to solve ? given: F = 0.24 N (at distance r) we have to find F'=? , at distance (r'=r/2) Step2 b) Formula Used: F = Gmlm2 p2 for distance r, 0. 24 = Gmlm2 (1) for distance r', F' = Gmlm2 p2 (2) (2) /(1) Gmlm2 F Gmlm2/r2 $ = (:)* = ()* F F' = 4F F = 4 * 0. 24 F = 0.96 N
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