1. To determine the potassium content of a sample, 1.275 g of the sample was dissolved in water and reacted with sodium tetraphenylborate, NaB(C6H5)4. This reaction produced the insoluble precipitate potassium phenylborate, KB(CHs)4 (FM = 358.33 g/mol). The potassium phenylborate precipitate was weighed and had a mass of 0.955 g. Calculate the percentage by mass of K (FM = 39.098 g/mol) in the sample. (Inspired by problem 7-6 in the Harris text). %3D
1. To determine the potassium content of a sample, 1.275 g of the sample was dissolved in water and reacted with sodium tetraphenylborate, NaB(C6H5)4. This reaction produced the insoluble precipitate potassium phenylborate, KB(CHs)4 (FM = 358.33 g/mol). The potassium phenylborate precipitate was weighed and had a mass of 0.955 g. Calculate the percentage by mass of K (FM = 39.098 g/mol) in the sample. (Inspired by problem 7-6 in the Harris text). %3D
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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![1. To determine the potassium content of a sample, 1.275 g of the sample was dissolved in water
and reacted with sodium tetraphenylborate, NaB(C6H5)4. This reaction produced the insoluble
precipitate potassium phenylborate, KB(C¿Hs)4 (FM = 358.33 g/mol). The potassium
phenylborate precipitate was weighed and had a mass of 0.955 g. Calculate the percentage by
mass of K (FM= 39.098 g/mol) in the sample. (Inspired by problem 7-6 in the Harris text).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F445178e5-eb66-4a17-8b6f-493656b3ff53%2Fd84606ca-90f0-4a03-a2d2-94bd3fd0dbe0%2Fgqophtd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. To determine the potassium content of a sample, 1.275 g of the sample was dissolved in water
and reacted with sodium tetraphenylborate, NaB(C6H5)4. This reaction produced the insoluble
precipitate potassium phenylborate, KB(C¿Hs)4 (FM = 358.33 g/mol). The potassium
phenylborate precipitate was weighed and had a mass of 0.955 g. Calculate the percentage by
mass of K (FM= 39.098 g/mol) in the sample. (Inspired by problem 7-6 in the Harris text).
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